Answer:
jump discontinuity at x = 0; point discontinuities at x = –2 and x = 8
Step-by-step explanation:
From the graph we can see that there is a whole in the graph at x=-2.
This is referred to as a point discontinuity.
Similarly, there is point discontinuity at x=8.
We can see that both one sided limits at these points are equal but the function is not defined at these points.
At x=0, there is a jump discontinuity. Both one-sided limits exist but are not equal.
Answer:
3x+7=10x+17
Step-by-step explanation:
1.9
10x
27x
Answer:
The width of the pathway is:
Step-by-step explanation:
To identify the width of the pathway, you must remember the area formula of a rectangle:
- Area of a rectangle = length * width.
From which the width can be cleared:
- Width of a rectangle = area / length.
We know that the length of the terrain was not modified since the pathway is in the perimeter of the rectangle (16 m) and that the new area is 240 m^2, so we only have to replace the cleared formula:
- Width of a rectangle = 240 m^2 / 16 m = 15 m.
The new width is equal to 15 meters, but since the question is not the total width but the width of the pathway, the width of the previously provided land must be subtracted from the value obtained.
- <u>Pathway width = Total width - Garden width.
</u>
- <u>Pathway width = 15m - 8m = 7 meters.</u>
Answer:
< CFE = 40°
Step-by-step explanation:
To better understand the solution, see attachment for the diagram.
Given:
BC parallel to DE
Measure of Arc BD = 58°
Measure of Arc DE = 142°
First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.
The line ST divides the arc BD and arc DE into half.
That is:
Arc SC = 1/2(arc BC) =1/2(58)
Arc SC = 29°
Arc TE = 1/2(arc DE) =1/2(142)
Arc TE = 71°
Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle
29° + Arc CE + 71° = 180°
Arc CE + 100° = 180°
Arc CE = 180-100
Arc CE = 80°
Inscribed angle = 1/2(intercepted angle)
<CFE = 1/2(Arc CE )
<CFE = 1/2(80)
< CFE = 40°
