How do you solve this? Please help me (i will give you 14 points)
1 answer:
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(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:
(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:
β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:
Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:
Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:
(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:
β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:
Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:
Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
Answer:
The coordinates of B is (3, - 5)
Step-by-step explanation:
A(6, 1)
C(2, -7)
Coordinates of point B such that AB = 1/3 × BC
Hence we have;
Therefore BC = 3/4 × AC
Hence, AB = 1/3 × BC = 1/3 × 3/4 × AC = 1/4 × AC
AC = √((6 - 2)² + (1 - (-7))²) = √(16 + 64) = √80 = 4·√5
AB = 1/4 × 4·√5 = √5
Therefore;
AB² = (x - 6)² + (y - 1)² = 5
Slope = (1 - (-7))/(6 - 2) = 2
Hence the y coordinate of B = -7 + sin(tan⁻¹(2)) ×√5 = -5
The x coordinate of B = 2 + cos(tan⁻¹(2)) ×√5 = 3
The coordinates of B = (3, - 5)