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EastWind [94]
1 year ago
15

Express 0.555... as a fraction in simplest form

Mathematics
2 answers:
Vika [28.1K]1 year ago
6 0

Answer:

111 /200

Step-by-step explanation:

0.555 × 1000 / 1 × 1000 = 555/1000

when reduced to fraction the answer is 111/200

cestrela7 [59]1 year ago
5 0

Answer:

0.40404040.

Step-by-step explanation:

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Can you Solve this 2y+4y=6-3y?
Licemer1 [7]

Answer:

\large\boxed{y=\dfrac{2}{3}}

Step-by-step explanation:

2y+4y=6-3y\\\\6y=6-3y\qquad\text{add}\ 3y\ \text{to both sides}\\\\6y+3y=6-3y+3y\\\\9y=6\qquad\text{divide both sides by 9}\\\\\dfrac{9y}{9}=\dfrac{6}{9}\\\\y=\dfrac{6:3}{9:3}\\\\y=\dfrac{2}{3}

3 0
2 years ago
Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin
tekilochka [14]

Answer:

1

p(b) =  \frac{1}{6}

2

p(k) =  \frac{1}{3}

3

P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

p(b) =  \frac{N}{n}

p(b) =  \frac{6}{36}

p(b) =  \frac{1}{6}

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

p(k) =  \frac{2}{6}

p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

3 0
2 years ago
According to the Rational Root Theorem, the following are potential roots of f(x) = 6x4 + 5x3 – 33x2 – 12x + 20. -5/2,-2, 1, 10/
stiks02 [169]
-5/2 is the answer. I just took the test and got it right.
8 0
2 years ago
Read 2 more answers
Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
Vinil7 [7]
Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied

Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.

Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.

Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.

Solutions are: (1, -4), (0, -3) , (2, -2)

4 0
2 years ago
Jalen bought 4 bottles of water, 2 bags of cashews, and a fruit salad. The cost of the fruit salad was $5. This expression was u
butalik [34]
The statment is correct but if you have to work out the value of x you need a total amount of the purchase without that or atleast some sort of value it is not possible to work out
3 0
2 years ago
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