1 year ago

In the diagram, DG = 12, GF = 4, EH = 9, and HF = 3

Mathematics

2 answers:

Wittaler [7]1 year ago

7 0

Answer:

The answer would be: C. ∠DFE is congruent to ∠GFH.

Step-by-step explanation:

sineoko [7]1 year ago

6 0

<span>The answer would be: C. ∠DFE is congruent to ∠GFH.

From the question, it is stated that the ratio of DF/GF and EF/HF would be 1:3. The ratio of two sides is already same so you can fulfil the two side criteria from SAS. The remaining is only the angle that should be between those two sides. The angle of DFE should be same with </span><span>GFH</span>

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A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r

eduard

Answer:

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Step-by-step explanation:

Given: Length= 2.5 m

Radius= 1.5 m

Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= $2\pi rh$

Considering, π= 3.14

⇒ lateral surface area of cylinder= $2\times 3.14\times 1.5\times 2.5$

⇒ lateral surface area of cylinder= $23.55 \ m^{2}$

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Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= $\frac{16500}{23.55} = 700.6369 \approx 701$

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

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