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2 years ago

Which of the following are exterior angles? Check all that apply.

Mathematics

1 answer:

Marina86 [1]2 years ago

6 0

Answer:

Step-by-step explanation:

Exterior angles can be described as the angles that are formed between the side of a polygon and the extended adjacent side of the polygon.

Or an exterior angle is the angle that is not inside the triangle formed.

The angles inside the triangle are interior angles.

Exterior angles are :

Interior angles are :

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Under the best conditions, a sprout has a 40% probability of blooming.

murzikaleks [220]

Answer:

Step-by-step explanation:

Im good at math

7 0

1 year ago

PLEASE HELP THANK YOUUUU Your group has $120 available for the banquet. Any other costs must be covered from selling tickets for

Keith_Richards [23]

Answer:

The cost C, of hosting the banquet with the services of Caterer One is;

C = $ 45·n

The cost C, of hosting the banquet with the services of Caterer Two is;

C = $250 + $ 28·n

The cost C, of hosting the banquet with the services of Caterer Three is;

C = $500 + $ 20·n

Step-by-step explanation:

The information includes;

The amount available to the group for the banquet = $120

The number of people attending the banquet = n

The cost incurred in hosting the banquet = C

The major costs in hosting the banquet are hall rental and caterer

The cost per caterer are as follows;

Caterer One

The cost per person including the hall = $45

Therefore, the cost incurred, C, in hosting the banquet using caterer one is equal;

C = n × $45 = $ 45·n

Caterer Two

The hall rental = $250

The cost per person = $28

Therefore, the cost incurred, C, in hosting the banquet using caterer two is equal;

C = $250 + n × $28 = $250 + $ 28·n

Caterer Three

The hall rental = $500

The cost per person = $20

Therefore, the cost incurred, C, in hosting the banquet using caterer three is equal;

C = $500 + n × $20 = $500 + $ 20·n.

5 0

2 years ago

Solve the following linear program using the graphical solution procedure: Max 5A + 5B s.t. 1A lessthanorequalto 100 1B lessthan

earnstyle [38]

<h2>Answer:</h2>

The optimal solution to the given linear programming problem exist at (100,50)

and the optimal solution is: 5A+5B= 750

<h2>Step-by-step explanation:</h2>

We are given a system of linear programming problem as follows:

Max 5A + 5B

s.t. A ≤ 100---------------(1)

B ≤ 80-------------(2)

2A+4B ≤400-------------(3)

which is given by:

A+2B ≤ 200

and A,B≥0

This means that the solution to this LPP will lie in the first quadrant.

( Since, both the variables A and B are greater than or equal to zero)

Now, we consider that A is represented by the x axis and B by y-axis.

We know that the optimal solution always exist at the boundary point.

Hence, by plotting these inequalities in the graph we get the boundary points as:

(0,0) , (0,80) , (100,0) , (100,50) and (40,80)

Now, we will check at which boundary point the optimal function is maximized .

Point Value of optimal function( 5A+5B)

(0,0) 0

(0,80) 400

(100,0) 500

(100,50) 750

(40,80) 600

The maximum value is obtained at (100,50).

and the value of the optimal solution is: 750

5 0

2 years ago

Which expression is equivalent to x Superscript negative five-thirds? StartFraction 1 Over RootIndex 5 StartRoot x cubed EndRoot

Anastasy [175]

Option B : $\frac{1}{\sqrt[3]{x^{5} } }$ is the expression equivalent to $x^{-\frac{5}{3}$

Explanation:

The given expression is $x^{-\frac{5}{3}$

Rewriting the expression $x^{-\frac{5}{3}$ using the exponent rule, $a^{-b}=\frac{1}{a^{b}}$

Hence, we get,

$\frac{1}{x^{\frac{5}{3} } }$

Simplifying, we get,

$\frac{1}{\left(x^{5}\right)^{\frac{1}{3}}}$

Applying the rule, $a^{\frac{1}{n}}=\sqrt[n]{a}$

Thus, we have,

$\frac{1}{\sqrt[3]{x^{5} } }$

Now, we shall determine from the options that which expression is equivalent to $x^{-\frac{5}{3}$

Option A: $\frac{1}{\sqrt[5]{x^{3} } }$

The expression $\frac{1}{\sqrt[5]{x^{3} } }$ is not equivalent to simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $\frac{1}{\sqrt[5]{x^{3} } }$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option A is not the correct answer.

Option B: $\frac{1}{\sqrt[3]{x^{5} } }$

The expression $\frac{1}{\sqrt[3]{x^{5} } }$ is equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $\frac{1}{\sqrt[3]{x^{5} } }$ is equivalent to $x^{-\frac{5}{3}$

Hence, Option B is the correct answer.

Option C: $-\sqrt[3]{x^5}$

The expression $-\sqrt[3]{x^5}$ is not equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $-\sqrt[3]{x^5}$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option C is not the correct answer.

Option D: $-\sqrt[5]{x^3}$

The expression $-\sqrt[5]{x^3}$ is not equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $-\sqrt[5]{x^3}$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option D is not the correct answer.

4 0

2 years ago

Read 2 more answers

Devin borrowed $1,058 at 13 percent for nine months. What will he pay in interest?

Viktor [21]

Devin borrowed $1,058 at 13 percent for nine months.

We have to calculate the interest paid.

Interest = $\frac{P \times R \times T}{100}$

Substituting the values of

Principal = $1058

Rate = 13%

Time = 9 months = $\frac{9}{12}$ year

Interest = $\frac{1058 \times 13 \times 9}{12 \times 100}$

Interest = 103.155

= 103.16

So, Devin will pay 103.16 as the interest.

Therefore, Option A is the correct answer.

8 0

2 years ago

Read 2 more answers