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yawa3891 [41]
2 years ago
15

A rectangular section of granite is being cut so that the length is 3 times the width. The perimeter of the section must be less

than 320 inches.
Which statement is true?

A.
The length of the granite must be at least 80 inches.
B.
The length of the granite must be less than 100 inches.
C.
The length of the granite must be at least 100 inches.
D.
The length of the granite must be less than 120 inches.
Mathematics
2 answers:
s344n2d4d5 [400]2 years ago
8 0

Answer:

D.

The length of the granite must be less than 120 inches.

Step-by-step explanation:

Let x inches be the widht of the section. If the length is 3 times the width, then the length is 3x inches.

The perimeter of the rectangle is

P=2(\text{width + length})

Hence,

P=2(x+3x)=2\cdot 4x=8x

The perimeter of the section must be less than 320 inches, so

8x

agasfer [191]2 years ago
6 0

Answer:

D.

The length of the granite must be less than 120 inches.

Step-by-step explanation:

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To solve 16x18, you may split it up into a smaller increment you understand. Like 16x2, which equals 32. (18/2 is 9) multiply 32 by 9. you get your answer 288.
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Ramina found the length of two pieces of ribbon to be 47.6 inches and 39.75 inches. Which is an effective estimation strategy fo
lukranit [14]

Answer:

<h3>Add 47.6 and 39.75, then round the answer</h3>

Step-by-step explanation:

If Ramina found the length of two pieces of ribbon to be 47.6 inches and 39.75 inches, the effective strategy of finding the sum of the two lengths is to:

1) First is to add the two values together

47.6 + 39.75

= (47+0.6)+(39+0.75)

= (47+39)+(0.6+0.75)

= 86 + 1.35

= 87.35

2) Round up the answer to nearest whole number.

87.35 ≈ 87 (note that we couldn't round up to 88 because the values after the decimal point wasn't up to 5)

Option C is correct

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2 years ago
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A sausage company makes two different kinds of hot dogs, regular and all-beef. Each pound of all-beef hot dogs requires 0.75 lb
Gre4nikov [31]

Answer:

  • 880 lbs of all-beef hot dogs
  • 2000 lbs of regular hot dogs
  • maximum profit is $3320

Step-by-step explanation:

We can let x and y represent the number of pounds of all-beef and regular hot dogs produced, respectively. Then the problem constraints are ...

  • .75x + 0.18y ≤ 1020 . . . . . . limit on beef supply
  • .30y ≤ 600 . . . . . . . . . . . . . limit on pork supply
  • .2x + .2y ≥ 500 . . . . . . . . . . limit on spice supply

And the objective is to maximize

  p = 1.50x + 1.00y

The graph shows the constraints, and that the profit is maximized at the point (x, y) = (880, 2000).

2000 pounds of regular and 880 pounds of all-beef hot dogs should be produced. The associated maximum profit is $3320.

8 0
2 years ago
Amy has a box containing 6 white, 4 red, and 8 black marbles. She picks a marble randomly. It is red. The second time, she picks
kati45 [8]

Answer: The probability that the fourth marble Amy picks is black =\frac{8}{15}

The probability that in the fifth attempt she will pick a red or a black marble P(R∩B) =\frac{5}{7}


Step-by-step explanation:

To find  the probability that in the fifth attempt she will pick a red or a black marble P(R∩B) .

The total marble in beginning=6+4+8=18

After 3 attempts, the total  marbles left=18-3=15

The number of black marbles =8

The probability that the fourth marble Amy picks is black =\frac{8}{15}

As four marble has already picked up, then the total marbles left in the box

=18-4=14

Now, as a red marble is already picked in 1st attempt , the number of red marbles in the box now= 4-1=3

And a black marble is already picked in fourth attempt , the number of black marbles in the box now= 8-1=7

Now P(R∩B)=P(R)+P(B)=\frac{3}{14}+\frac{7}{14}=\frac{10}{14}=\frac{5}{7}

7 0
2 years ago
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