Question

An airline has 83% of its flights depart on schedule. It has 68% of its flight depart and arrive on schedule. Find the probability that a flight that departs on schedule also arrives on schedule. Round the answer to two decimal places.

Answer 1

The probability that a flight that departs on schedule also arrives on schedule
83%×68%=56%

Answer 2

Answer:

Hence, the probability is:

0.82

Step-by-step explanation:

Let A denote the event that the flight departs on time.

Let B denote the event that the flight arrives on schedule.

Also, A∩B denotes the event that the flight that departs on time also arrives on schedule.

Let P denotes the probability of an event.

We are asked to find:

                              P(B|A)

We know that:

$P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}$

Hence, we have:

P(A)=0.83 x.

P(A∩B)=0.68 x.

where x are the total number of flights.

Hence,

$P(B|A)=\dfrac{0.68x}{0.83x}\\\\P(B|A)=0.82$

Hence,  the probability that a flight that departs on schedule also arrives on schedule is:

                                     0.82