answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tankabanditka [31]
2 years ago
15

The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)

is the point at which the terminal ray of angle Theta intersects the unit circle. What are the values for the cosine and cotangent functions for angle Theta? cosine theta = Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, cotangent theta = negative 1 cosine theta = StartFraction StartRoot 2 EndRoot Over 2 EndFraction, cotangent theta = 1 cosine theta = StartFraction StartRoot 2 EndRoot Over 2 EndFraction, cotangent theta = negative one-half cosine theta = Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, cotangent theta = one-half
Mathematics
2 answers:
Ierofanga [76]2 years ago
5 0

Answer:

\cot(x)  =  - 1 \: and \:  \cos(x)  =  -  \frac{ \sqrt{2} }{2}

Step-by-step explanation:

The given point is :

( -  \frac{ \sqrt{2} }{2}, \frac{ \sqrt{2} }{2})

This point is in the second quadrant.

This means:

\cos(x) = -  \frac{ \sqrt{2} }{2},  \sin(x) =  \frac{ \sqrt{2} }{2})

Cotangent is cosine/sine

\cot(x)=\frac{ \frac{ \sqrt{2} }{2} }{ -  \frac{ \sqrt{2} }{2} }  =  - 1

Taya2010 [7]2 years ago
4 0

Answer:

A.

Step-by-step explanation:

You might be interested in
How might you prove your observations about the slope of a midsegment in part d using algebra and x- and y-coordinates? Briefly
ioda

Answer: I can use variables to represent the coordinates of the vertices for a general triangle ABC. then I can calculate the midpoints of the sides in terms of the same variables, and calculate the slope of each midsegment showing that the expression for the slope of a midsegment is the same as the expression for the slope of the third side of the triangle proves that the two are parallel.

Step-by-step explanation: this is word for word btw!

4 0
2 years ago
Read 2 more answers
Which of the following functions gives the radius, r(v), of a conical artifact that is 20 inches tall as a function of its volum
irinina [24]
<h3><u>Radius as function of volume is:</u></h3>

r(v) = \sqrt{\frac{3v}{20 \pi }}\ inches

<em><u>Solution:</u></em>

<em><u>The volume of cone is given as</u></em>:

v = \frac{1}{3}\pi r^{2} h

Where,

r is the radius

h is the height

From given,

height = 20 inches

From formula,

v = \frac{1}{3}\pi r^{2} h

Rearrange , so that r is alone in left side of equation

3v = \pi r^2 h\\\\\pi r^2 h = 3v\\\\r^2 = \frac{3v}{\pi h}\\\\Take\ square\ root\ on\ both\ sides\\\\r = \sqrt{\frac{3v}{\pi h}}

Substitute h = 20

r = \sqrt{\frac{3v}{20 \pi }}

Thus, radius as function of volume is:

r(v) = \sqrt{\frac{3v}{20 \pi }}\ inches

4 0
2 years ago
A pizza restaurant sells containers of juice that it marks up 75 percent above its wholesale cost. If the restaurant marks up ea
Len [333]
75% of what is 0.90
0.75x = 0.90
x = 0.90/0.75
x = 1.20 <== restaurant pays $ 1.20 wholesale
4 0
2 years ago
Read 2 more answers
If m∠ABC = 45° and m∠ECD = 45°, which statement explains whether the AA similarity postulate can be used to determine whether ΔB
LekaFEV [45]

Answer:

No, the AA similarity postulate cannot be used because a reflection over line f will establish that ∠ABC and ∠DEC are not congruent.

Step-by-step explanation:

Data provided in the question

m∠ABC = 45°

m∠ECD = 45°

Based on the above information, the ΔBAC ~ ΔEDC could be determined by seeing the given options

As we can see that from the last option the AA could not be postulated as it creates a reflection over the line plus the ∠ABC and ∠DEC is not congruent

Therefore the last option is correct

7 0
1 year ago
On February 1, the electricity meter reading for the Smith residence was 19,423 kilowatt hours. On March 1, the meter read 20,28
Karolina [17]
A. How many kilowatt hours of electricity did the Smiths use during February?

Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
20,288 kilowatt hours - 19,423 kilowatt hours =
865 kilowatt hours
Answer: The Smiths used 865 kilowatt hours of electricity during February

b. How many kilowatt hours did they use during March?

Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
21,163 kilowatt hours - 20,288 kilowatt hours =
875 kilowatt hours
Answer: The Smiths used 875 kilowatt hours of electricity during March
8 0
2 years ago
Other questions:
  • What is a rational number between 6.2 and 6.3
    10·1 answer
  • A cube with side length 2f is stacked on another cube with side length 3g2. Choose the expression that represents the total volu
    13·2 answers
  • How much water do you add  to make 12% sugar syrup using 5g sugar?
    10·2 answers
  • A teacher wanted to buy a chair, a bookshelf, two tables and a desk. She spent $900 for all five items and the chair and the des
    5·1 answer
  • Translate to an inequality. Use the variable x for next year's salary.
    11·1 answer
  • Solve Multi-Step Problems - Quiz - Level D
    7·1 answer
  • Among a large group of patients recovering from shoulder injuries, it is found that 22% Visit both a physical therapist and a ch
    11·1 answer
  • (a) calculate the value of the correlation coefficient between sale price and size. (give the answer to three decimal places.) r
    7·1 answer
  • Write 5,806 in scientific notation
    6·2 answers
  • Which shows the pre-image of quadrilateral W'X'Y'Z' before the figure was rotated according to the rule (x, y) → (–x, –y)?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!