We know the triangle is an isosceles triangle. So, we use the Pythagorean Theorem.
a^2+b^2=c^2
The c would be 22, because it's the longest edge. Now find a or b. They are the same, that is how you find the two sides of the triangle for part A.
To find the area of the triangle, the forumla is a=hb/2
Plug in the numbers for that formula and the answer would be found for part B.
I hope I helped.
The answer is: 
The explanation is shown below:
1. Cynthia rounds the number, which is identified as 
, to one decimal place and the result is 6.3.
2. Based on this, we know that could have been between 6.25 and 6.35. Therefore, the error interval for is given by:
Where 
indicates that the value 6.25 is included and 
indicates that the value 6.35 is not included (Because if had been exactly 6.35, Cynthia would round up to 6.4).
Cost of chicken wings at Buffalo Bills = 8 wings for $7
Cost of 1 wing at Buffalo Bills = 
Cost of chicken wings at Buffalo Mild Wings = 12 wings for $10
Cost of 1 wing at Buffalo Mild Wings = 
Cost of chicken wings at Wingers = 20 wings at $17
Cost of 1 wing at Wingers = 
Hence, comparing all the three costs per wing, we can see that Buffalo Mild Wings is serving chicken wings at lowest price of $0.833 per wing.
Let stadium 1 be the one on the left and stadium 2 the one on the right.
Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).
For the next part we need to use the trigonometric function of tangent.
As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)
Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)
Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)
Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)
Thus, the distance between both stadiums is 2215.49-461.46= 1754.03 m
Correcting the answer to whole number gives you 1754 m which is the option C.
Answer:
Length of diagonal of the rectangle=
√( length) ²+( breadth) ²
=√(20) ²+(12) ²
=√400+144
√544 m
. '. Length of fence= √544 m
Perimeter of the triangle formed by the diagonal of the rectangle =(12+20+√544)
=(32+√544) m
