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2 years ago

Josephine bought 8 packets of biscuits. Each packet had a mass of 500 g

Mathematics

1 answer:

Nataly_w [17]2 years ago

7 0

Answer: 985 g

Step-by-step explanation:

Total mass = 8 × 500g = 4000g

Let the three new packs be X, Y, and Z, for first, second, and third pack respectively.

4000g = X + Y + Z

let's put X and Z in terms of Y, since we're trying to solve for the second pack.

X = 2Y, and Z = Y + 60

Therefore,

4000 = X + Y + Z

4000 = 2Y + Y +Y + 60

4000 = 4Y +60

4000 - 60 = 4Y

3940 = 4Y

3940 ÷ 4 = Y

985g = Y = mass of the second pack

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Answer:

The radius of the circle is 5 units

Step-by-step explanation:

Given in the question,

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a point in the circle = (1,5)

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with the centre being at the point (h, k) and the radius being r.

Plug values in the equation

(1 – (-3))² + (5 – 2)² = r²

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2 years ago

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Answer:

hexahedron: triangle or quadrilateral or pentagon
icosahedron: quadrilateral or pentagon

Step-by-step explanation:

Hexahedron

A hexahedron has 6 faces. A regular hexahedron is a cube. 3 square faces meet at each vertex.

If the hexahedron is not regular, depending on how those faces are arranged, a slice near a vertex may intersect 3, 4, or 5 faces. The first attachment shows 3- and 4-edges meeting at a vertex. If those two vertices were merged, then there would be 5 edges meeting at the vertex of the resulting pentagonal pyramid.

A slice near a vertex may create a triangle, quadrilateral, or pentagon.

Icosahedron

An icosahedron has 20 faces. The faces of a regular icosahedron are all equilateral triangles. 5 triangles meet at each vertex.

If the icosahedron is not regular, depending on how the faces are arranged, a slice near the vertex may intersect from 3 to 19 faces.

A slice near a vertex may create a polygon of 3 to 19 sides..

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2 years ago

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Step-by-step explanation:

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2 years ago

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1 year ago

Read 2 more answers

25. To produce the graph of the function y=0.5cos(0.5x), what transformations should be applied to the graph of the parent funct

soldi70 [24.7K]

Answer:

C. A horizontal stretch to produce a period of $2\pi$ and a vertical compression.

Step-by-step explanation:

We are given the parent function as $y= \cot x$

It is given that, transformations are applied to the parent function in order to obtain the function $y=0.5\cot (0.5x)$ i.e. $y=\frac{1}{2}\cot (\frac{x}{2})$

That is, we see that,

The parent function $y= \cot x$ is stretched horizontally by the factor of $\frac{1}{2}$ which gives the function $y=\cot (\frac{x}{2})$ .

Further, the function is compressed vertically by the factor of $\frac{1}{2}$ which gives the function $y=\frac{1}{2}\cot (\frac{x}{2})$ .

Now, we know,

If a function f(x) has period P, then the function cf(bx) will have period $\frac{P}{|b|}$ .

Since, the period of $y= \cot x$ is $\pi$ , so the period of $y=\frac{1}{2}\cot (\frac{x}{2})$ is $\frac{\pi}{1/2}$ = $2\pi$

Hence, we get option C is correct.

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2 years ago