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olga_2 [115]
2 years ago
6

Josephine bought 8 packets of biscuits. Each packet had a mass of 500 g

Mathematics
1 answer:
Nataly_w [17]2 years ago
7 0

Answer: 985 g

Step-by-step explanation:

Total mass = 8 × 500g = 4000g

Let the three new packs be X, Y, and Z, for first, second, and third pack respectively.

4000g = X + Y + Z

let's put X and Z in terms of Y, since we're trying to solve for the second pack.

X = 2Y, and Z = Y + 60

Therefore,

4000 = X + Y + Z

4000 = 2Y + Y +Y + 60

4000 = 4Y +60

4000 - 60 = 4Y

3940 = 4Y

3940 ÷ 4 = Y

985g = Y = mass of the second pack

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HELP PLEASE. Which regression equation best fits these data?
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B. y = -0.58x^2 -0.43x +15.75

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Answer:

Correct answer is:

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Step-by-step explanation:

Given that Number of bracelets with yellow beads is represented by y

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Total money raised by bracelets with yellow beads = Number of bracelets sold \times Money raised by sale of one such bracelet = 5y

Also Given that Number of bracelets with Orange beads is represented by r

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Given that total money raised by sale of both type of bracelets is $660.

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5 0
1 year ago
Andre and Diego were each trying to solve 2x+6=3x−8. Describe the first step they each make to the equation. The result of Andre
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Comparing the result of Andre's work with the original, we see that the "3x" term on the right is missing, and the x-term on the left is 3x less than it was. It is clear that Andre subtracted 3x from both sides of the equation.

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<u>Diego</u>

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<em>Comment on their work</em>

IMO, Diego has the right idea, as his result leaves the x-term with a positive coefficient. He can add 8 and he's finished, having found that x=14.

Andre can subtract 6 to isolate the variable term, and that will give him -x=-14. This requires another step to get to x=14. Sometimes minus signs get lost, so this would not be my preferred sequence of steps.

As a rule, I like to add the opposite of the variable term with the least (most negative) coefficient. This results in the variable having a positive coefficient, making errors easier to avoid.

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