All categories

2 years ago

Which statements are true regarding the area of circle

Mathematics

2 answers:

Pavlova-9 [17]2 years ago

6 0

Question:

Which statements are true regarding the area of circle D? Select two options.

The area of the circle depends on the square of the radius.

The area of circle D is 36Pi centimeters squared.

The area of circle D is 324Pi centimetres squared

The area of the circle depends on the square of pi.

The area of the circle depends on the central angle.

Answer:

The following statements are true regarding the area of circle D:

The area of the circle depends on the square of the radius
The area of circle D is 324Pi centimeters

Step-By-Step Explanation:

As we know, the formula for area of the circle is given by,

$A=\pi r^{2}$

Where, r = radius of the circle. In figure, CD = radius = 18 cm

So, the circle area can be measured as

$A=\pi(18)^{2}=324 \pi \mathrm{cm}^{2}$

From this, concluding that the circle area depends on radius square and its value is $324 \pi \mathrm{cm}^{2}$ . Hence, the statement given in option A and C are correct (reveals that option B is incorrect).

As the Pi is constant, the circle radius cannot depend on Pi value and Option D also incorrect. The area of sector of circle only depends on ratio of central angle to entire circle (So option E also incorrect).

nadya68 [22]2 years ago

3 0

Answer:

A and C

Step-by-step explanation:

You might be interested in

Describe 83 in two other ways

S_A_V [24]

Answer:

83 is a prime number. 83 is also an uneven number.

Step-by-step explanation:

4 0

2 years ago

Let v⃗ 1=⎡⎣⎢⎢⎢0.50.50.50.5⎤⎦⎥⎥⎥, v⃗ 2=⎡⎣⎢⎢⎢0.50.5−0.5−0.5⎤⎦⎥⎥⎥, v⃗ 3=⎡⎣⎢⎢⎢0.5−0.5−0.50.5⎤⎦⎥⎥⎥. v→1=[0.50.50.50.5], v→2=[0.50.5−0

Morgarella [4.7K]

Answer:

can you post a question that actually has the right graphics

Step-by-step explanation:

6 0

2 years ago

Crop researchers plant 15 plots with a new variety of corn. The yields in bushels per acre are: 138.0 139.1 113.0 132.5 140.7 10

son4ous [18]

There is a relationship between confidence interval and standard deviation:
$\theta=\overline{x} \pm \frac{z\sigma}{\sqrt{n}}$
Where $\overline{x}$ is the mean, $\sigma$ is standard deviation, and n is number of data points.
Every confidence interval has associated z value. This can be found online.
We need to find the standard deviation first:
$\sigma=\sqrt{\frac{\sum(x-\overline{x})^2}{n}$
When we do all the calculations we find that:
$\overline{x}=123.8\\ \sigma=11.84$
Now we can find confidence intervals:
$($90\%,z=1.645): \theta=123.8 \pm \frac{1.645\cdot 11.84}{\sqrt{15}}=123.8 \pm5.0\\($95\%,z=1.960): \theta=123.8 \pm \frac{1.960\cdot 11.84}{\sqrt{15}}=123.8 \pm 5.99\\ ($99\%,z=2.576): \theta=123.8 \pm \frac{2.576\cdot 11.84}{\sqrt{15}}=123.8 \pm 7.87\\$
We can see that as confidence interval increases so does the error margin. Z values accociated with each confidence intreval also get bigger as confidence interval increases.
Here is the link to the spreadsheet with standard deviation calculation:
https://docs.google.com/spreadsheets/d/1pnsJIrM_lmQKAGRJvduiHzjg9mYvLgpsCqCoGYvR5Us/edit?usp=sharing

6 0

2 years ago

Which of the following are true statements about any regular polygon? Check all that apply. A. It is a quadrilateral. B. All of

sesenic [268]

A regular polygon is a closed figure
All its angles are equal in measure.
and all its sides are congruent

3 0

2 years ago

Read 2 more answers

ANSWER ALL 5 PARTS.

N76 [4]

A function $f$ from a set A to a set B is defined as a relation that assings to each element $x$ in the set A exactly one element $y$ in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is $x$ feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let $x$ be the width of the tomato patch, then the function that matches this statement is:

$\boxed{Wa(x)=\frac{x}{2}}$

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

 $\boxed{La(x)=x+2}$

2. Area of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then the area of a rectangle is the product of the length and width. So:

 $A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}$

3. Combined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

 $Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}$

4. Write the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:

 $Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x$

5. Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

 $31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06$

Therefore the area of the remaining space is:

 $\boxed{Aa(7.06)=7.06ft^{2}}$

6 0

2 years ago