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spayn [35]
2 years ago
14

The class president collected data on 150 randomly selected 17-year-olds at his school. He surveyed students on if they had a jo

b and driver’s license. The results are shown below. 93 of the 17-year olds had a job 128 of the 17-year olds had a driver’s license 76 of the students had both a job and a driver’s license Part A: Construct a two-way frequency table summarizing the data. Part B: What percent of the students who have a job, do not have a driver’s license?

Mathematics
1 answer:
telo118 [61]2 years ago
8 0

Answer:

Step-by-step explanation:

Part A can be seen in the attached picture below. Since there are 76 students that have both a license and a job we need to subtract 76 from each to get the amount that only have either a license or a job as seen in the table. Also we can see from the table that it sums up to 145 students, meaning that 5 students do not have neither a job or a license.

Part B, to calculate this we need to divide the amount of students that ONLY have a job by the total amount of students that have a job (since the rest of those students also have a license) Therefore:

17 / 93 = 0.1828

Now we can multiply this result by 100 to get the percentage.

0.1828 * 100 = 18.28%

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Answer:

2.7%

Step-by-step explanation:

Since the probability of having and accident or exceed the deductible does not depend on the color of the car, the events are independent.

Recall that if two events A and B with probabilities P(A), P(B) of occurrence are independent, then

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2 years ago
Catron evaluates the expression (negative 9) (2 and two-fifths) using the steps below.
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The error is:

She incorrectly broke up 2 and two-fifths.

Option A is correct option.

Step-by-step explanation:

We need to  describes Catron’s error?

The steps are:

Step 1: (Negative 9) (2 + two-fifths)

Step 2: (Negative 9) (Negative 2) + (negative 9) (two-fifths)

Step 3: Negative 18 + (negative 9) (two-fifths)

Step 4: (negative 27) (two-fifths)

Solution: Negative StartFraction 54 over 5 EndFraction = Negative 10 and four-fifths

The error is:

She incorrectly broke up 2 and two-fifths.

Option A is correct option.

<u>Solving </u>

Solving the equation by removing the error:

Step 1: (Negative 9) (2 + two-fifths)

taking LCM of 2 and two-fifths (2/5)

Step 2: (Negative 9) (twelve-fifths)

Step 3: (Negative 9*twelve)-fifths

Step 4: Negative one hundred and eight- fifths

Solution: Negative StartFraction -108 over 5 EndFraction = Negative one hundred and eight- fifths

Keywords: Solving Expressions

Learn more about Solving Expressions at:

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Answer:

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