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2 years ago

It costs 480 to rent an apartment on the Gold Coast for a weekend. Last year it cost $400 how would you calculate the increase

Mathematics

2 answers:

Inessa [10]2 years ago

8 0

Answer:

The increase in rent is 20%.

Step-by-step explanation:

Last year rent of an apartment on the Gold Coast for a weekend was $400.

This year it costs $480

Now we calculate the increase of rent

( 480 - 400 ) / 400 = 80 / 400 = 0.20

To convert into percentage we multiply it by 100 = 0.20 × 100 = 20%

The increase in rent is 20%.

Umnica [9.8K]2 years ago

3 0

You could write a set of equations or use the interest formula, A(t)=P(1+r/n)^nt
where p equals the principal amount, r equals the rate/ percentage of interest, n equals the compounding periods and t equals time

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Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFraction right-parenthes

lina2011 [118]

Answer:

$y-\frac{1}{3}=\frac{3}{4}(x-4)$

Step-by-step explanation:

we know that

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

In this problem we have

$(x_1,y_1)=(4,\frac{1}{3})$

$m=\frac{3}{4}$

substitute the given values

$y-\frac{1}{3}=\frac{3}{4}(x-4)$

therefore

y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)

6 0

1 year ago

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David drove a distance of 187km, correct to 3 significant figures. He used 28 litres of petrol, correct to 2 significant figures

mote1985 [20]

David drove a distance (d) of 187km, to 3 significant figures. He used 28 litres of petrol (p), to 2 significant figures.
The petrol consumption (c) in km per litre is given by the formula: c= d/p
By considering bounds, work out the value of c, to a suitable degree of accuracy. You must show your working and give a reason for your answer. I'm not totally comfortable with sig figs, but I believe that the answer can only be expressed as accurately as least number of sig figs of any data used in the computations.....thus ....the answer should be rounded to 2 sig figs

So

187 / 28 = 6.67 ⇒ 6.7 km / L [rounded to 2 sig figs ].

8 0

1 year ago

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An experiment on memory was performed, in which 16 subjects were randomly assigned to one of two groups, called "Sentences" or "

FromTheMoon [43]

Answer:

There is no significant difference between the averages.

Step-by-step explanation:

Let's call

$\large X_{sentences}$ the mean of the “sentences” group

$\large S_{sentences}$ the standard deviation of the “sentences” group

$\large X_{intentional}$ the mean of the “intentional” group

$\large S_{intentional}$ the standard deviation of the “intentional” group

Then, we can calculate by using the computer

$\large X_{sentences}=28.75$

$\large S_{sentences}=3.53553$

$\large X_{intentional}=31.625$

$\large S_{intentional}=1.40788$

$\large X_{sentences}-X_{intentional}=28.75-31.625=-2.875$

The standard error of the difference (of the means) for a sample of size 8 is calculated with the formula

$\large \sqrt{(S_{sentences})^2/8+(S_{intentional})^2/8}$

So, the standard error of the difference is

$\large \sqrt{(3.53553)^2/8+(1.40788)^2/8}=1.34546$

In order to see if there is a significant difference in the averages of the two groups, we compute the interval of confidence of 95% for the difference of the means corresponding to a level of significance of 0.05 (5%).

If this interval contains the zero, we can say there is no significant difference.

Since the sample size is small, we had better use the Student's t-distribution with 7 degrees of freedom (sample size-1), which is an approximation to the normal distribution N(0;1) for small samples.

We get the $\large t_{0.05}$ which is a value of t such that the area under the Student's t distribution outside the interval $\large [-t_{0.05}, +t_{0.05}]$ is less than 0.05.

That value can be obtained either by using a table or the computer and is found to be

$\large t_{0.05}=2.365$

Now we can compute our confidence interval

$\large (X_{sentences}-X_{intentional}) \pm t_{0.05}*(standard \;error)=-2.875\pm 2.365*1.34546$

and the confidence interval is

[-6.057, 0.307]

Since the interval does contain the zero, we can say there is no significant difference in these samples.

6 0

2 years ago

On a test, leo is asked to completely factor the polynomial 3x3 – 3x 5x2 – 5. he uses double grouping to get (x2 – 1)(3x 5). has

Agata [3.3K]

No, Leo's answer is not a product of prime polynomials because x2 – 1 can be factored. This is a difference of squares. He should continue factoring to get

(x – 1)(x + 1)(3x + 5).

8 0

2 years ago

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Yvette exercises 14 days out of 30 in one month. What is the ratio of the number of days she exercises to the number of days in

Anestetic [448]

Answer:

7 to 15, 7:15, 7/15

Step-by-step explanation:

Ratios can be written as:

a to b

a:b

a/b

We want to find the ratio of exercise days to days in the month. She exercises 14 days out of 30 days in the month. Therefore,

a= 14

b= 30

14 to 30

14:30

14/30

The ratios can be simplified. Both numbers can be evenly divided by 2.

(14/2) to (30/2)

7 to 15

(14/2) : (30/2)

7:15

(14/2) / (30/2)

7/15

3 0

1 year ago

Read 2 more answers