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2 years ago

Patrick drank 0.75 liter of water Monday before jogging.he drank 0.8liter of water after his jog.

1 answer:

5 0

If you want to find out how much he drank in total, its simple. Just add 0.75 and 0.8

¹0.75 Liters
+ 0.8 Liters
---------
1.55 Liters
(make sure to add the units AKA: liters)

Therefore,
Patrick drank 1.55 Liters of water in total.

Hope this helps and have a great day :)

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You and a friend are playing a game by tossing two coins. If both coins land

Novosadov [1.4K]

c. No. You have a probability of winning, while your friend has a
probability of winning.
Or it’s A

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2 years ago

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Pete corporation produces bags of peanuts. It's fixed cost is $18,900. Each bag sells for $2.17 with a unit cost of $1.27. What

pentagon [3]

Answer:

in units: 18,900

in dollars: $ 41,013

Step-by-step explanation:

The break even point is the sales dollar amount or sales in unit at whichthe operating income of the firm equals to zero: $\frac{Fixed\:Cost}{Contribution \:Margin} = Break\: Even\: Point_{units }$

Where:

$\frac{Contribution \: Margin}{Sales \: Revenue} = Contribution \: Margin \: Ratio$

<em><u>Contribution margin:</u></em>

2.17 - 1.27 = 1 dollar per unit

Break even:

$18,900 fixed cost / $1 per unit = 18,900 units

Then, in sales:

18,900 x $2.17 each = 41.013‬

break even point:

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2 years ago

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A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de

strojnjashka [21]

Answer:

a) P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

a= μ-3.16*σ , b= μ+3.16*σ

b) P(Y≥ μ+3*σ ) ≥ 0.90

b= μ+3*σ

Step-by-step explanation:

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y = the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 → 1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90 → 1- σ²/(σ²+λ²)= 1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

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2 years ago

Find the unit price of 60lbs of honey for $123.99. Round your answer to the nearest cent if necessary.

astraxan [27]

The unit price is $2.07 per lb (pound).

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2 years ago

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Which of the following options have the same value as 60\%60%60, percent of 949494?

garri49 [273]

<h2>Answer:</h2>

The correct options are:

Choice A

Choice C

and Choice E

<h2>Step-by-step explanation:</h2>

We are asked to find the value of:

60% of 94

We know that: it is represented as:

$60\%\ of\ 94=\dfrac{60}{100}\times 94\\\\\\=0.6\times 94$

Choice A)

$0.06\cdot 940$

We know that:

$0.6\times 94$ could also be written as:

$0.06\times 940$

Since we multiplied and divide by 10 such that:

$=0.6\times 94\times \dfrac{10}{10}\\\\\\=\dfrac{0.6}{10}\times (94\times 10)\\\\\\=0.06\times 940$

Hence, option: A is correct.

Choice B)

$0.6\cdot 940$

This option is incorrect.

Since by choice A we get that the correct expression is: $0.06\cdot 940$

Choice C)

We get:

$\dfrac{3}{5}\cdot 94$

This option is correct.

Since,

$60\%\ of 94\ is:\\\\\\=\dfrac{60}{100}\cdot 94\\\\\\=\dfrac{3}{5}\cdot 94$

Choice D)

$60\cdot 94$

This option is incorrect because the actual expression is:

$0.6\cdot 94$

Choice E)

[/tex]\dfrac{60}{100}\cdot 94[tex]

This is the correct expression.

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2 years ago

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