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Bad White [126]
1 year ago
9

In 2010, a city's population was 1,405,233 and it was decreasing at a rate of 1.1%. At this rate when will the city's population

fall below 1,200,000?
a. 2024
b. 2027
c. 2036
d. 2049
Mathematics
1 answer:
frez [133]1 year ago
7 0
The equation
                                            P(t) = 1405233 * (1 - 0.011)^(t)
models the population at t years after 2010. Then, when P(t) = 1,200,000, we have
                                 1200000 = 1405233 * (0.989)^t
                                  (0.989)^t = 1200000/1405233
                                                t = log(1200000/1405233)/log(0.989)
                                                t = 14.27 years
This means 14.27 years after 2010. Therefore, the answer to this question is 2024.
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MatroZZZ [7]

Answer:

8.86cm^2

Step-by-step explanation:

Given the rectangle of 3cm by 4cm and a circle of 1 cm inside it:

The Area of the shaded portion =Area of Rectangle-Area of Circle

Area of a Rectangle=Length X Width=3 X 4 =12cm^2

Area of the circle =\pi r^2=\pi X 1^1=3.142cm^2

Area  of the shaded portion=12-3.142

=8.86cm^2

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1 year ago
Tom and jerry have to stuff and seal 63 envelopes for a new marketing campaign. Jerry can stuff and seal 15 envelopes alone in 2
zheka24 [161]
Chile—. Ion understand, good luck tho.....
7 0
2 years ago
Which statements are true of functions? Check all that apply. All functions have a dependent variable. All functions have an ind
Mars2501 [29]
The true statemens are:


All function have (at least) a dependent variable. That is why you can write y = f(x), x is the independent variable, while y depends on x values, so y is the independent variable. 


All function have and independent variable (explained above).


A horizontal line is an example of a funcitional relationship (because given a value of x, you can always tell the value of y)



The other statements are false:

<span>The range of a function includes its domain is false.

Domain are the values that x can take and the range are the values that the function (y) can take. One is not included in the other.


A vertical  line is an example of a functional relationship is false, because you can not tell the value of y for any value of x. 


</span>
<span>Each output value of a function can correspond to only one input value is false.  An output can be generated by more than one value of x. The horizontal line is an example of that: the same value of y (output) corresponde to any value of x.</span>

 



8 0
1 year ago
Read 3 more answers
Have you ever been frustrated because you could not get a container of some sort to release the last bit of its contents? The ar
snow_tiger [21]

Answer:

Yes. There is enough evidence to support the claim that the remaining toothpaste is significantly is less than 10% of the advertised net content.

Step-by-step explanation:

The sample of the remaining toothpaste is: [.53, .65, .46, .50, .37].

This sample has a size n=5, a mean M=0.502 and standard deviation s=0.102.

M=\dfrac{1}{5}\sum_{i=1}^{5}(0.53+0.65+0.46+0.5+0.37)\\\\\\ M=\dfrac{2.51}{5}=0.502

s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{5}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.53-(0.502))^2+...+(0.37-(0.502))^2]}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.001)+(0.022)+(0.002)+(0)+(0.017)]}\\\\\\            s=\sqrt{\dfrac{0.04188}{4}}=\sqrt{0.01047}\\\\\\s=0.102

The 10% of the advertised content is:

0.10\cdot 6.0\;oz=0.6\:oz

Hypothesis test for the population mean:

The claim is that the remaining toothpaste is significantly is less than 10% of the advertised net content.

Then, the null and alternative hypothesis are:

H_0: \mu=0.6\\\\H_a:\mu< 0.6

The significance level is 0.05.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.102}{\sqrt{5}}=0.046

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{0.502-0.6}{0.046}=\dfrac{-0.098}{0.046}=-2.148

The degrees of freedom for this sample size are:

df=n-1=5-1=4

This test is a left-tailed test, with 4 degrees of freedom and t=-2.148, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.049) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the remaining toothpaste is significantly is less than 10% of the advertised net content.

7 0
2 years ago
The perimeter of a rectangle is 343434 units. Its width is 6.56.56, point, 5 units.
Andru [333]
This is annoying


the perimiter is 34 units
the width is 6.5 units


ok.
perimiter=2(Length+Width)
P=2(L+W)
solve for L
distribute
P=2L+2W
minus 2W
P-2W=2L
divide by 2
\frac{P-2W}{2}=L

given that P=34 units and W=6.5 units
\frac{34-2(6.5)}{2}=L


the equation would be L=\frac{P-2W}{2} or L=\frac{P}{2}-W

3 0
2 years ago
Read 2 more answers
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