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Bad White [126]
2 years ago
9

In 2010, a city's population was 1,405,233 and it was decreasing at a rate of 1.1%. At this rate when will the city's population

fall below 1,200,000?
a. 2024
b. 2027
c. 2036
d. 2049
Mathematics
1 answer:
frez [133]2 years ago
7 0
The equation
                                            P(t) = 1405233 * (1 - 0.011)^(t)
models the population at t years after 2010. Then, when P(t) = 1,200,000, we have
                                 1200000 = 1405233 * (0.989)^t
                                  (0.989)^t = 1200000/1405233
                                                t = log(1200000/1405233)/log(0.989)
                                                t = 14.27 years
This means 14.27 years after 2010. Therefore, the answer to this question is 2024.
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Express these numbers in standard form (a)5730(b)0.23(c)0.000231(d)7150000(e)500.8
alisha [4.7K]

Answer:

5730 = 5.73×10³

0.23 = 2.3×10‐¹

0.000231 = 2.31×10-⁴

7150000 = 7.15×10⁶

500.8 = 5.008×10²

8 0
2 years ago
Express 3.222......in p/q form​
beks73 [17]

Answer:

3.22222......  = \frac{29}{9}

Step-by-step explanation:

In this question we have to convert the number given in recurrent decimals into fraction.

Recurrent decimal number is 3.22222.......

Let x = 3.2222.........   -------(1)

Multiply this expression by 10.

10x = 32.2222........... -------(2)

Now subtract the expression (1) from (2),

10x = 32.22222.....

<u>    x = 3.22222.......</u>

9x = 29

x = \frac{29}{9}

Therefore, recurrent decimal number can be written as \frac{29}{9} which is in the form of \frac{p}{q}.

6 0
2 years ago
Mr. Smith works on a temporary basis. The mean length of each job he gets is three months. If the amount of time he spends betwe
Eduardwww [97]

Answer:

Mr Smith gets a new job, every 5 months on the average.

Step-by-step explanation:

Mr Smith spends an average of 3 months on every job he gets.

Then he spends an average of 2 months in between jobs.

Meaning, on the average, if he has a job, he does it for 3 months, then leaves, lends the next 2 months without a job, then gets another job at the end of the 2 months without a job and then he repeats the cycle of 3 months on the job, 2 months without the job.

So, on the average it takes Mr. Smith, (3+2) months to get a new job.

6 0
2 years ago
Izumi is running on a quarter-mile oval track. After running 110 yards, his coach records his time as 16 seconds.
pickupchik [31]

Answer:

14.04 miles per hour

Step-by-step explanation:

The problem is asking for Izumi's speed. The formula of speed is:

  • s = \frac{d}{t} , where "s" means speed, "d" means distance and "t" means time.

The problem is also asking for the unit<u> miles per hou</u>r (\frac{miles}{hour}) so, this means that we have to know how many miles Izumi ran, given that the problem only mentioned<u> yards (110 yards).</u>

Let's convert 110 yards to miles, provided that he Izumi ran 1,760 yards in a mile.

  • 110 yards ÷ 1760 \frac{yards}{mile} = 0.0625 miles (this is the distance covered by Izumi in miles)

Let's go back again to the formula: s = \frac{d}{t}

s = \frac{0.0625 miles}{16 seconds} = 0.0039 \frac{miles}{sec}

Since, the we arrived at a miles per second unit, we have to convert it to miles per hour.

So, if a minute has 60 seconds, then an hour has 3,600 seconds.

Thus, 0.0039 \frac{miles}{sec} × 3,600 \frac{seconds}{hour} = 14.04 miles per hour (the answer)

3 0
2 years ago
Annabelle arranged her 42 building blocks into 3 rows of 14 blocks. Then, she rearranged them into 6 rows of 7 blocks. What two
cupoosta [38]

Answer:

21 rows 2 blocks

1 row 42 blocks

Step-by-step explanation:

Given that:

Number of blocks with Annabelle = 42

First arrangement = 3 rows 14 blocks

Second arrangement = 6 rows 7 blocks

To find:

The other two factor pairs that could be used to rearrange the blocks again?

Solution:

Here, we will have to find the factor pairs of total number of blocks present with Annabelle.

i.e. 42

First of all, let us have a look at the factor pairs of 42.

42 = 3\times 14\\42 = 6\times 7\\42 = \underline{2\times 21}\\42 = \underline{1\times 42}

Therefore, the other two factor pairs can be 2, 21 and 1, 42.

The other two possible factor pairs are:

21 rows 2 blocks

1 row 42 blocks

4 0
2 years ago
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