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Hitman42 [59]
2 years ago
14

At most, Alana can spend $40 on carnival tickets. Ride tickets cost $4 each, and food tickets cost $2 each. Alana buys at least

16 tickets. The system of inequalities represents the number of ride tickets, r, and the number of food tickets, f, she buys.
r + f ≥ 16

4r + 2f ≤ 40



What is the maximum number of ride tickets she can buy?

4
6
10
12
Mathematics
2 answers:
evablogger [386]2 years ago
5 0
We can let r be the number of food tickets and f be the number of food tickets. Since Alana can spend at most $40, that means the total of price bought for r and f must be less than or equal to $40. In addition, since Alana buys at least 16 tickets, this also means that the total of r and f is 16. Mathematically, we have these inequalities: (1) 4r + 2f ≤ 40 and (2) r + f ≥ 16 Multiplying -2 in (2), we have 4r + 2f ≤ 40 -2r - 2f ≤ 32 Adding both inequalities, 2r ≤ 8 r ≤ 4 Since r must be less than or equal to 4.Thus the answer is <span>A.</span>
ozzi2 years ago
3 0

Answer:

A

Step-by-step explanation:

4 on EDGE

just did it

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Rewrite in simplest radical form x 5/6 x 1/6
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Answer:

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Step-by-step explanation:

Given

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Required

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This implies that

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Solve Exponents

x^{\frac{5}{6}}/x^{\frac{1}{6}} = x^{\frac{5 - 1}{6} }

x^{\frac{5}{6}}/x^{\frac{1}{6}} = x^{\frac{4}{6} }

Simplify exponent to lowest fraction

x^{\frac{5}{6}}/x^{\frac{1}{6}} = x^{\frac{2}{3} }

Using laws of indices:

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This implies that

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tia_tia [17]

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