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DochEvi [55]
2 years ago
7

Fourteen runners in a marathon had these race times, in hours,

Mathematics
1 answer:
Ymorist [56]2 years ago
7 0

Answer:

Please find attached the histogram for the marathon runners

Step-by-step explanation:

The given data is presented as follows;

2.21

2.25

2.76

3.1

3.3

3.5

3.6

3.77

3.8

4.23

4.25

4.25

4.6

4.9

From the data, we have;

The frequency or number of runners that run between 0 and 1 hour = 0

The frequency or number of runners that run between 1 and 2 hours = 0

The frequency or number of runners that run between 2 and 3 hours = 3

The frequency or number of runners that run between 3 and 4 hours = 6

The frequency or number of runners that run between 4 and 5 hours = 5

With the above frequencies for the different data ranges, the histogram of the given data is then constructed as attached.

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In order to find the answer you would need to explain the graphs.

Step-by-step explanation:

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Three cats and three dogs, A, B, C, D, E, and F, live on a street in three different-coloured houses. Each house hosts one cat a
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Answer:

1) A is a cat; B is a dog; C is a cat; D is a dog; E is a dog; F is a cat

2) A lives with B in a yellow house; C lives with D in a blue house; E lives with F in a red house.

Step-by-step explanation:

Step 1: First we identify the animals as cats or dogs

A is a cat

B is a Dog

Since B can live with C, C is a cat

Since D can live with A, D is a dog

F is a cat since it can live with D

E is therefore, a dog

Step 2: We then identify the house each two animals live in pairs of a cat and a dog

D lives in a blue house

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E lives in a red house since it does not live with A or in a yellow house

F lives with E in a red house since E does not live with A

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5 0
2 years ago
Given circle X with radius 10 units and chord AB with length 12 units, what is the length of segment CX, which bisects the chord
andrew-mc [135]
Consider the circle with center X, as shown in the figure. 

Draw the diameter of the circle which is parallel to cherd AB, as shown in the figure.

Since the diameter and AB are parallel, then the line segment XC which bisects AB at C, will be perpendicular to AB.

SO triangle XCB is a right triangle. Thus the length of CX, by the Pythagorean theorem is  

\sqrt{ XB^{2}- CB^{2}} = \sqrt{ 10^{2}- CB^{6}}= \sqrt{100-36}= \sqrt{64}=8 units.


Answer: 8 units

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$13.20

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Make w the subject of the formula y-aw=2w-1
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Answer: <span>w = [ y + 1] / [a + 2]

Solution step by step:
</span>
1) given <span>formula: y-aw=2w-1

2) transpose aw and - 1

2w + aw = y + 1

3) common factor w:

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