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Lina20 [59]
2 years ago
11

2 tens 1 one x 10 unit form

Mathematics
1 answer:
Olin [163]2 years ago
3 0
21x10 is 210 your welcome
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Jun and deron are applying for summer jobs at a local restaurant. after interviewing them, the restaurant owner says, "the proba
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At an intersection, the red-light times are normally distributed with a mean time of 3 minutes and a standard deviation of 0.25
denpristay [2]

Percent of red lights last between 2.5 and 3.5 minutes is 95.44% .

<u>Step-by-step explanation:</u>

Step 1: Sketch the curve.

The probability that 2.5<X<3.5 is equal to the blue area under the curve.

Step 2:

Since μ=3 and σ=0.25 we have:

P ( 2.5 < X < 3.5 ) =P ( 2.5−3 <  X−μ < 3.5−3 )

⇒ P ( (2.5−3)/0.25 < (X−μ)/σ < (3.5−3)/0.25)

Since, Z = (x−μ)/σ , (2.5−3)/0.25 = −2 and (3.5−3)/0.25 = 2 we have:

P ( 2.5<X<3.5 )=P ( −2<Z<2 )

Step 3: Use the standard normal table to conclude that:

P ( −2<Z<2 )=0.9544

Percent of red lights last between 2.5 and 3.5 minutes is 0.9544(100) = 95.44% .

3 0
2 years ago
A consensus forecast is the average of a large number of individual analysts' forecasts. Suppose the individual forecasts for a
stealth61 [152]

Answer:

a) 0.954

b) 0.937

c) 0.891  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  6 percent

Standard Deviation, σ = 1.3 percent

We are given that the distribution of particular interest rate is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(At least 3.8 percent.)

P(x \geq 3.8)

P( x \geq 3.8) = P( z \geq \displaystyle\frac{3.8 - 6}{1.3}) = P(z > -1.69)

= 1 - P(z < -1.69)

Calculation the value from standard normal z table, we have,  

P(x \geq 3.8) = 1 - 0.046 = 0.954 = 95.4\%

b) P(At most 8 percent)

P(x \leq 8) = P(z \leq \displaystyle\frac{8-6}{1.3}) = P(z \leq 1.53)

Calculating the value from the standard normal table we have,

P( x \leq 8) =0.937= 93.7\%

c) P(Between 3.8 percent and 8 percent. )

P(3.8 \leq x \leq 8) = P(-1.69 \leq z \leq 1.53)\\\\= P(z \leq 1.53) - P(z < -1.69)\\= 0.937 - 0.046 = 0.891 = 89.1\%

P(3.8 \leq x \leq 8) = 89.1\%

3 0
2 years ago
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