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Lina20 [59]
2 years ago
11

2 tens 1 one x 10 unit form

Mathematics
1 answer:
Olin [163]2 years ago
3 0
21x10 is 210 your welcome
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Define a function print_total_inches, with parameters num_feet and num_inches, that prints the total number of inches. note: the
Leona [35]

Answer:

2

I am taking my first programming course, so my apologies if this is a dumb question/possibly classified by the wrong category on this site. One of the exercise problems I am working on is the following:

Define a function print_total_inches, with parameters num_feet and num_inches, that prints the total number of inches. Note: There are 12 inches in a foot. Ex:

print_total_inches(5, 8) prints:

Total inches: 68

Step-by-step explanation:

5 0
2 years ago
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What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?
astraxan [27]
ANSWER


The value of the expression is
- 1


EXPLANATION

Method 1: Rewrite as product of
{i}^{2}


The expression given to us is,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}


We use the fact that
{i}^{2}  =  - 1
to simplify the above expression.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{1}  \times {i}^{3}   \times {i}^{2}   \times {i}^{4}


This implies,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{2}  \times {i}^{2}   \times {i}^{2}   \times {i}^{2} \times {i}^{2}


We substitute to obtain,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  - 1 \times  - 1  \times  - 1\times  - 1 \times  - 1


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  1 \times   1  \times  - 1 =  - 1


Method 2: Use indices to solve.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{0 + 1 + 2 + 3 + 4}



This implies that,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{10}




{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (  {{i}^{2}} )^{5}


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (   - 1 )^{5}   =  - 1


8 0
2 years ago
Read 2 more answers
Use synthetic division to solve (x^3 + 1) ÷ (x – 1). What is the quotient?
soldi70 [24.7K]
What are your choices?
7 0
2 years ago
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Solve for x:<br> 3(5x + 10) + 10 = 6x - (x + 10)
34kurt

Answer:

x= -5

Step-by-step explanation:

3(5x+10)+10=6x-(x+10)

15x+30+10=6x-x-10

15x+40=5x-10

15x-5x=-10-40

10x=-50

x=-5

8 0
1 year ago
Read 2 more answers
How to factorise 5h^2-12hg​
bonufazy [111]

Answer:

h(5h-12g)

Step-by-step explanation:

5h^2-12hg

When we factor expressions, we look for factors within the terms that are alike, or in other words, we look for common factors. Here, 5h^2 and 12hg only have one common factor: h. Therefore, to factorize this expression, divide both terms by h.

= h(\frac{5h^2}{h}-\frac{12hg}{h}  )\\= h(5h-12g)

Now, we've "carried" h out of the expression and have therefore factored it.

I hope this helps!

7 0
1 year ago
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