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Amanda [17]
1 year ago
13

Conrad is an architect who has just been sued because a building he helped design has collapsed and injured several people. What

type of insurance would help him with court costs and settlements.
A.legal malpractice B.universal
B.medical malpractice C.general liability D.catastrophic
Mathematics
1 answer:
Troyanec [42]1 year ago
6 0
General liability insurance (answer C) would help Conrad  with court costs and settlements in a situation when he is sued because his design collapsed and injured several people. General liability insurance is a insurance that can protect the insured person from a variety of claims including body injury, property damage. A single accident can result in lawsuit. 
The cost of general liability insurance is impacted by several factors: the business type, the location of the business, the level of risk the business is exposed to, the number of employees.

You might be interested in
Allison plays basketball and last season she made a total of 87 shots (two- or three- point shots). Her points total was 191. Ho
yarga [219]

Answer:

17

Step-by-step explanation:

Let the number of 2 point shots be t.

Let the number of 3 point shots be h.

Allison made 87 shots and scored 191 total points. This implies two things:

t + h = 87 ________(1)

2t + 3h = 191 ______(2)

Let us eliminate t by multiplying (1) by 2 and subtracting from (2):

=> 2t + 3h = 191

 -  <u>2t + 2h = 174</u>

     <u>          h  = 17 </u>

<u />

Therefore, she made 17 three point shots.

4 0
2 years ago
Data show that men between the ages of 20 and 29 in a general population have a mean height of 69.3​ inches, with a standard dev
dangina [55]

Data show that men between the ages of 20 and 29 in a general population have a mean height of 69.3​ inches, with a standard deviation of 2.5 inches. a baseball analyst wonders whether the standard deviation of heights of​ major-league baseball players is less than 2.5 inches. the heights​ (in inches) of  20 randomly selected players are shown in the table.

72 74 71 72 76

70 77 75 72 72

77 72 75 70 73

74 75 73 74 74

What are the correct hypotheses for this  test?

The null hypothesis is H₀?: ____ 2.5

The alternative hypothesis is H₁?: ____  2.5

Calculate the value of the test statistic.

x² = _____ (Round to three decimal places)

Answer:

Null hypothesis, H₀: σ = 2.5

Alternative hypothesis,  Hₐ: μ<2.5

Test statistic = 12.920

Step-by-step explanation:

Given Data shows that:

men between the ages of 20 and 29 in a general population have a mean height of 69.3​ inches, with a standard deviation of 2.5 inches

We consider a random sample of 20 selected baseball players.

Therefore;

The Null and Alternative hypothesis are as follows:

The Null hypothesis is the standard deviation of the heights of major league baseball players is not less than 2.5 inches.

Null hypothesis, H₀: σ = 2.5

On the other hand: The Alternative hypothesis is the standard deviation of the heights of major league baseball players is less than 2.5 inches.  

Alternative hypothesis,  Hₐ: μ<2.5

The Mean Calculation is:

\bar{x} = \frac{1}{2} \sum x_i

= \frac{1}{20} (72+74+...+74) \\ \\ = \frac{1468}{20} \\ \\ =73.4

The sample standard deviation is:

s = \sqrt{\frac{1}{n-1} \sum (x_1 - \bar{x})^2 }

= \sqrt{\frac{1}{20-1} \sum (72-73.4)^2 + ...+(74-73.4)^2 }  \\ \\ =  \sqrt{4.25}  \\ \\ = 2.06

The test statistics is now determined as :

x^2 = \frac{(n-1)s^2}{\sigma^2} \\ \\ = \frac{(20-1)(2.06)^2}{(2.5)^2}  \\ \\ = \frac{19*4.25}{6.25} \\ \\ = \frac{80.75}{6.25} \\ \\ = 12.920

4 0
2 years ago
Jenna offers regular haircuts for $25 and haircuts plus coloring for $42.This weekend had a total of 24 clients and Jenna earned
shepuryov [24]
<u><em>Answer:</em></u>
Jenna did 16 regular haircuts
Jenna did 8 haircuts with coloring

<u><em>Explanation:</em></u>
Assume that the number of regular haircuts is x and the number of haircuts plus coloring is y

<u>We are given that:</u>
<u>1- Jenna did a total of 24 clients, this means that:</u>
x + y = 24
This can be rewritten as:
x = 24 - y ...............> equation I

<u>2- regular haircuts cost $25, haircuts plus coloring cost $42 and she earned a total of $736. This means that:</u>
25x + 42y = 736 ..........> equation II

<u>Substitute with equation I in equation II and solve for y as follows:</u>
25x + 42y = 736
25(24-y) + 42y = 736
600 - 25y + 42y = 736
17y = 136
y = 8

<u>Substitute with y in equation I to get x as follows:</u>
x = 24 - y
x = 24 - 8
x = 16

<u>Based on the above:</u>
Jenna did 16 regular haircuts
Jenna did 8 haircuts with coloring

Hope this helps :)
5 0
2 years ago
Uma pessoa realizou uma compra que foi financiada em três parcelas mensais e iguais a R$ 350,00, o financiamento foi realizado s
lisabon 2012 [21]

Answer: Amount of purchase would be $393.70.

Step-by-step explanation:

One person made a purchase that was financed in three monthly installments and equal to $ 350.00, the financing was made at the compound interest rate of 48% a.a. Determine the amount of the purchase.

Since we have given that

Principal = $350.00

Rate of compounded monthly = 48%

Number of months = 3

So, the amount of purchase would be

Amount=350(1+\dfrac{0.48}{12})^3\\\\Amount=350(1+0.04)^3\\\\Amount=350(1.04)^3\\\\Amount=\$393.70

Hence, Amount of purchase would be $393.70.

5 0
1 year ago
Two new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes. Drug
lakkis [162]

Answer:

4.979044478499338 × 10²⁶

Step-by-step explanation:

Combination can be used to determine the number of ways the mice can be selected for the drugs (A, B) and the control group.

Combination factorial is define by  ⁿCr = \frac{n!}{(n-r)!r!}

21 group of mice receiving Drug A  can be selected in ⁶⁰C₂₁ = \frac{60!}{21!39!}

(60 - 21 = 39 ) mice remained for selection of 21 mice for the second drug

Drug B 21 mice can be chosen with ³⁹C₂₁ = \frac{39!}{21!18!}

( 39 - 21 = 18)  remained for control with ¹⁸C₁₈ = \frac{18!}{18!0!}

The number of ways the mice can be chosen for drug A, drug B and the control = ⁶⁰C₂₁ × ³⁹C₂₁ × ¹⁸C₁₈ = \frac{60!}{21!39!} × \frac{39!}{21!18!} × \frac{18!}{18!0!} = 4.979044478499338 × 10²⁶

8 0
2 years ago
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