Answer:
9/20, or 0.45 mile.
Step-by-step explanation:
To find the area of a rectangle, multiply length times width. In this problem we are given both the length and width.
×
is just 9/20, which is 0.45.
A scale drawing of a rectangular park is 5 inches wide and 7 inches ong. The actal prake is 280 yards long. What is the area of
1 answer:
Given:
A scale drawing of a rectangular park is 5 inches wide and 7 inches long.
The actual park is 280 yards long.
To find:
The area of the actual park.
Solution:
Length of drawing = 7 inches
Length of actual park = 280 yards
The scale factor is
7 inches : 280 yards
1 inches : 40 yards
The width of the drawing is 5 inches. So, the width of actual part is
The area of the actual park is
Therefore, the area of the actual park is 56000 sq. yards.
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Answer:
a) the length of the wire for the circle =
b)the length of the wire for the square =
c) the smallest possible area = 126.02 in² into two decimal places
Step-by-step explanation:
If one piece of wire for the square is y; and another piece of wire for circle is (60-y).
Then; we can say; let the side of the square be b
so 4(b)=y
b=
Area of the square which is L² can now be said to be;
On the otherhand; let the radius (r) of the circle be;
2πr = 60-y
Area of the circle which is πr² can now be;
Total Area (A);
A =
=
For the smallest possible area;
∴
If we divide through with (2) and each entity move to the opposite side; we have:
By cross multiplying; we have:
2πy = 480 - 8y
collect like terms
(2π + 8) y = 480
which can be reduced to (π + 4)y = 240 by dividing through with 2
∴ since , we can determine for the length of the circle ;
60-y can now be;
=
=
=
=
also, the length of wire for the square (y) ;
The smallest possible area (A) =
= 126.0223095 in²
≅ 126.02 in² ( to two decimal places)