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tekilochka [14]
1 year ago
7

A scale drawing of a rectangular park is 5 inches wide and 7 inches ong. The actal prake is 280 yards long. What is the area of

the actual park, in square yards?
Mathematics
1 answer:
Roman55 [17]1 year ago
7 0

Given:

A scale drawing of a rectangular park is 5 inches wide and 7 inches long.

The actual park is 280 yards long.

To find:

The area of the actual park.

Solution:

Length of drawing = 7 inches

Length of actual park = 280 yards

The scale factor is

7 inches : 280 yards

1 inches : 40 yards

The width of the drawing is 5 inches. So, the width of actual part is

40\times 5=200 yards

The area of the actual park is

Area=Length \times width

Area=280\times 200

Area=56000

Therefore, the area of the actual park is 56000 sq. yards.

You might be interested in
Which decimals written in expanded form are greater than 5.3? Check all that apply. 5 + 0.3 + 0.00 5 + 0.3 + 0.001 (5 × 1) + (2
Ksenya-84 [330]

Answer:

Any number in form of x.y = x (1) + 1/10 (y)

where x = 5 & y > 3 , or x > 5

Step-by-step explanation:

Expanded form of 5.3 = 5 (1) + 3 (1/10)

Some decimals written in expanded form that are greater than 5.3    :

5 (1) + 4 (1/10) = 5.4

6 (1) + 2 (1/10) = 6.2  

3 0
1 year ago
A hospital finds that 22% of its accounts are at least 1 month in arrears. A random sample of 425 accounts was taken. What is th
GenaCL600 [577]

Answer:

8.85% probability that fewer than 82 accounts in the sample were at least 1 month in arrears

Step-by-step explanation:

For each account, there are only two possible outcomes. Either they are at least 1 month in arrears, or they are not. The probability of an account being at least 1 month in arrears is independent from other accounts. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.22, n = 425

So

\mu = E(X) = np = 425*0.22 = 93.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{425*0.22*0.78} = 8.54

What is the probability that fewer than 82 accounts in the sample were at least 1 month in arrears

This probability is the pvalue of Z when X = 82. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{82 - 93.5}{8.54}

Z = -1.35

Z = -1.35 has a pvalue of 0.0885.

8.85% probability that fewer than 82 accounts in the sample were at least 1 month in arrears

8 0
1 year ago
Each year the soccer team, Peterson United, plays 25 games at their stadium. The owner of Peterson United claimed that last year
Mars2501 [29]
Total Attendence = Mean Attendence × No. of Incidents
= 24,500 × 25
= 612,500.
7 0
1 year ago
Read 2 more answers
A county is in the shape of a rectangle that is 60 miles by 70 miles and has a population of 50,000. What is the average number
lakkis [162]

Answer:

The correct answer is:

12

Step-by-step explanation:

Length of county = 70 miles

breadth of county = 60 miles

area of county (rectangle) = Length × Breadth = 60 × 70 = 4,200 sqaure miles

population of county = 50,000

Therefore, to find the average number of people living on each square mile of the county, we will assume that the whole population is equally distributed in the county, hence the population per square mile is calculated thus:

Total area = 4,200 square miles

total population = 50,000

This means that:

4,200 square miles contains 50,000 people

4,200 sq. miles = 50,000 people

∴ 1 sq. mile = 50,000 ÷ 4,200 = 11.9 = 12 people (to the nearest whole number)

therefore number of people living per square mile = 12

5 0
2 years ago
Suppose that Kevin can choose to get home from work by car or bus. When he chooses to get home by car, he arrives home after 7 p
astraxan [27]

Answer:

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm = 0.838

Step-by-step explanation:

Let the probability that Kevin arrives home after 7 pm be P(L)

Probability that Kevin uses the bus = P(B)

Probability that Kevin uses the car = P(C)

Probability of arriving home after 7 pm if the car was taken = P(L|C) = 4% = 0.04

Probability of arriving home after 7 pm if the bus was taken = P(L|B) = 15% = 0.15

The bus is cheaper, So, he uses the bus 58% of the time.

P(B) = 58% = 0.58

P(C) = P(B') = 1 - P(B) = 1 - 0.58 = 0.42

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm = P(B|L)

The conditional probability P(A|B) is given mathematically as

P(A|B) = P(A n B) ÷ P(B)

Hence, the required probability, P(B|L) is given as

P(B|L) = P(B n L) ÷ P(L)

But we do not have any of P(B n L) and P(L)

Although, we can obtain these probabilities from the already given probabilities

P(L|C) = 0.04

P(L|B) = 0.15

P(B) = 0.58

P(C) = 0.42

P(L|C) = P(L n C) ÷ P(C)

P(L n C) = P(L|C) × P(C) = 0.04 × 0.42 = 0.0168

P(L|B) = P(L n B) ÷ P(B)

P(L n B) = P(L|B) × P(B) = 0.15 × 0.58 = 0.087

P(L) = P(L n C) + P(L n B) = 0.0168 + 0.087 = 0.1038 (Since the bus and the car are the two only options)

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm

= P(B|L) = P(B n L) ÷ P(L)

P(B n L) = P(L n B) = 0.087

P(L) = 0.1038

P(B|L) = (0.087/0.1038) = 0.838150289 = 0.838

Hope this Helps!!!

8 0
1 year ago
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