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1 year ago

Which number has a value between -8.423 and -8.395?

Mathematics

1 answer:

pav-90 [236]1 year ago

5 0

Answer:

Step-by-step explanation:

Jmeu eimejrimr

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The thickness of a conductive coating in micrometers has a density function of 600x-2 for 100μm < x < 120 μm and zero for

ELEN [110]

Calculator can help you

4 0

2 years ago

The time it takes to deliver a pizza (from time of phone call to delivery at door) follows a normal distribution with a mean (µ)

Yuki888 [10]

Answer:

99.87% of the store’s total delivery orders will be delivered to consumers with charge

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 45, \sigma = 5$

If a pizza store’s policy is, "Orders delivered within one hour or they’re free!", what percentage of the store’s total delivery orders will be delivered to consumers with charge?

Within one hour, which is 60 minutes. So this is the pvalue of Z when X = 60.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 45}{5}$

$Z = 3$

$Z = 3$ has a pvalue of 0.9987

99.87% of the store’s total delivery orders will be delivered to consumers with charge

5 0

1 year ago

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D = {(x, y) |

Bas_tet [7]

Answer:

$M=168k$

$(\bar{x},\bar{y})=(5,\frac{85}{28})$

Step-by-step explanation:

Let's begin with the mass definition in terms of density.

$M=\int\int \rho dA$

Now, we know the limits of the integrals of x and y, and also know that ρ = ky², so we will have:

$M=\int^{9}_{1}\int^{4}_{1}ky^{2} dydx$

Let's solve this integral:

$M=k\int^{9}_{1}\frac{y^{3}}{3}|^{4}_{1}dx$

$M=k\int^{9}_{1}21dx$

$M=21k\int^{9}_{1}dx=21k*x|^{9}_{1}$

So the mass will be:

$M=21k*8=168k$

Now we need to find the x-coordinate of the center of mass.

$\bar{x}=\frac{1}{M}\int\int x*\rho dydx$

$\bar{x}=\frac{1}{M}\int^{9}_{1}\int^{4}_{1}x*ky^{2} dydx$

$\bar{x}=\frac{k}{168k}\int^{9}_{1}\int^{4}_{1}x*y^{2} dydx$

$\bar{x}=\frac{1}{168}\int^{9}_{1}x*\frac{y^{3}}{3}|^{4}_{1}dx$

$\bar{x}=\frac{1}{168}\int^{9}_{1}x*21 dx$

$\bar{x}=\frac{21}{168}\frac{x^{2}}{2}|^{9}_{1}$

$\bar{x}=\frac{21}{168}*40=5$

Now we need to find the y-coordinate of the center of mass.

$\bar{y}=\frac{1}{M}\int\int y*\rho dydx$

$\bar{y}=\frac{1}{M}\int^{9}_{1}\int^{4}_{1}y*ky^{2} dydx$

$\bar{y}=\frac{k}{168k}\int^{9}_{1}\int^{4}_{1}y^{3} dydx$

$\bar{y}=\frac{1}{168}\int^{9}_{1}\frac{y^{4}}{4}|^{4}_{1}dx$

$\bar{y}=\frac{1}{168}\int^{9}_{1}\frac{255}{4}dx$

$\bar{y}=\frac{255}{672}\int^{9}_{1}dx$

$\bar{y}=\frac{255}{672}8=\frac{2040}{672}$

$\bar{y}=\frac{85}{28}$

Therefore the center of mass is:

$(\bar{x},\bar{y})=(5,\frac{85}{28})$

I hope it helps you!

3 0

2 years ago

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, 1) and (0, 3). Everything to th

Allushta [10]

Answer:

$y>\frac{2}{3}x+3$

Step-by-step explanation:

step 1

Determine the slope of the dashed line

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

(-3,1) and (0,3)

substitute

$m=\frac{3-1}{0+3}$

$m=\frac{2}{3}$

step 2

Find the equation of the dashed line in slope intercept form

$y=mx+b$

we have

$m=\frac{2}{3}$

$b=3$ ---> given problem

substitute

$y=\frac{2}{3}x+3$

step 3

Find the equation of the inequality

we know that

Is a dashed line and everything to the left of the line is shaded

$y>\frac{2}{3}x+3$

see the attached figure to better understand the problem

8 0

1 year ago

Read 2 more answers

Danny Henry made a waffle on his six-inch-diameter circular griddle using batter containing a half a cup of flour. Using the sam

Mekhanik [1.2K]

Answer:

He'll need 288 cups to make a waffle on his 24 foot diameter circular griddle.

Step-by-step explanation:

In order to find out how much batter Danny needs we first need to compute the area of the first pans, since it is a circular pan their area is given by A = 2*pi*r. So we have:

Area of the first pan = 2*pi*(6/2) = 18.84 square inches

Area of the second pan = 2*pi*(24/2) = 75.36 square foots

We now need to convert these values to be in the same unit, we'll convert from square foots to square inches:

Area of the second pan = 75.36 * (12)^2 = 10851.84 square inches

We can now use a proportion knowing that the batter and the thickness of the waffles are the same. If 0.5 cup of flour can make a waffle on 18.84 square inches then x cup of flour can make a waffle on 10851.85 square inches. Writing this in a mathematical form, we have:

0.5/x = 18.84/10851.84

18.84x = 0.5*10851.85

x = 10851.85*0.5/18.84 =288 cups

7 0

2 years ago