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maxonik [38]
2 years ago
9

Which number has a value between -8.423 and -8.395?

Mathematics
1 answer:
pav-90 [236]2 years ago
5 0

Answer:

Step-by-step explanation:

Jmeu eimejrimr

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Equation that equals 69?
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3x23=69 is the equation that has the sum 69
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An angle t is drawn from the center of the unit circle. Find a formula in terms of t for the straight line distance d between th
Doss [256]

Answer:

d = \sqrt{2}\cdot \sqrt {1-\cos t - \sin t}

Step-by-step explanation:

Let suppose that one of the radii meets the circle at the point (1,0). The straight line distance formula is:

d = \sqrt{(\cos t - 1)^{2}+(\sin t - 1)^{2}}

d = \sqrt{(\cos^{2}t - 2\cdot \cos t + 1)+(\sin^{2}t - 2\cdot \sin t + 1)}

d = \sqrt{2-2\cdot (\cos t + \sin t )}

d = \sqrt{2}\cdot \sqrt {1-\cos t - \sin t}

5 0
2 years ago
Below are boxplots that summarize the weights (in pounds) of large samples from two breeds of dog: the Anatolian Shepherd and th
koban [17]

Answer:

(a) The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of both plots is also same that is 75 pounds.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively

(b) Any data point which is greater than 155 or smaller than 80 will be considered an outlier.

Step-by-step explanation:

A box plot is a graph which shows five statistical characteristics of a data set.

1. Maximum value

2. Minimum value

3. Median

4. Upper Interquartile

5. Lower interquartile

(a) Compare the distributions of weights for the two dog breeds

Please refer to the attached diagram of the question.

The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of Anatolian Shepherd is,

Range = Maximum value - Minimum value

Range = 175 - 100 = 75 pounds

The range of Black Russian Terrier is,

Range = Maximum value - Minimum value

Range = 155 - 80 = 75 pounds

Therefore, the range of both plots is also same that is 75 pounds.

A box-plot is considered to be normally distributed when the median is at the center of upper quartile and lower quartile.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively distributed.

(b) What weights would a Black Russian Terrier have to be to be considered an outlier?

An outlier is a data point in the data set that is very different from the other data points.

In this case, the maximum and minimum values in the Black Russian Terrier box-plot are

Maximum = 155

Minimum = 80

Therefore, any data point which is greater than 155 or smaller than 80 will be considered an outlier.

5 0
2 years ago
What does 5x-2=6+x equal to
zheka24 [161]

Answer: 2

Step-by-step explanation:

honestly just get mathpapa for math , its so easy

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A snack food manufacturer buys corn for tortilla chips from two cooperatives, one in Iowa and one in Illinois. The price per uni
aleksandrvk [35]

Answer:

a. <u>x1 = No. of units to purchase from Iowa</u>

   <u>x2 = No. of units to purchase from Illinois</u>

<u></u>

b. <u>Min 6x1 + 5.5x2</u>

<u></u>

c. <u>x1 + x2 ≥ 12000</u>

   <u>x1 ≤ 8000</u>

   <u>x2 ≥ 6000</u>

Step-by-step explanation:

a. We can consider the variables x1 and x2 as:

<u>x1 = No. of units to purchase from Iowa</u>

<u>x2 = No. of units to purchase from Illinois</u>

<u></u>

b. Price per unit of Iowa corn = $6

   Price per unit of Illinois corn = $5.5

Objective function that would minimize the total cost can be written as:

<u>Min 6x1 + 5.5x2</u>

<u></u>

c. The manufacturer needs at least 12000 units of corn which means that the combined number of units from Iowa and Illinois must be greater than or equal to  12000. So, we can write:

x1 + x2 ≥ 12000

The Iowa cooperative can supply up to 8000 units which means that the value of x1 must not be greater than 8000. So, we can write:

x1 ≤ 8000

Similarly, the Illinois cooperative can supply at least 6000 units which means that the value of x2 must not be less than 6000. So, we can write:

x2 ≥ 6000.

The constraints for these conditions are:

<u>x1 + x2 ≥ 12000</u>

<u>x1 ≤ 8000</u>

<u>x2 ≥ 6000</u>

6 0
2 years ago
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