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riadik2000 [5.3K]
2 years ago
5

Mr. Shamir employs two part-time typists, Inna and Jim, for his typing needs. Inna charges $15 an hour and can type 6 pages an h

our, while Jim charges $18 an hour and can type 8 pages per hour. Each typist must be employed at least 8 hours per week to keep them on the payroll. If Mr. Shamir has at least 208 pages to be typed, how many hours per week should he employ each typist to minimize his typing costs?

Mathematics
1 answer:
coldgirl [10]2 years ago
3 0

Answer:

The minimum cost would be 480$ when Inna works for 8 hours and Jim works for 20 hours.

Step-by-step explanation:

We are given the following information in the question:

Charges for 1 hour for Inna = $15

Number of pages typed by Inna in 1 hour = 6

Charges for 1 hour for Jim = $18

Number of pages typed by Jim in 1 hour = 8

Let x be the number of hours Inna work and let y be the number of hours Jim work.

Total cost = 15x + 18y

We have to minimize this cost.

Then, we can write the following inequalities:

6x + 8y \geq 208\\x \geq 8\\y \geq 8\\

The corner points as evaluated from graph are: (8,20) and (24,8)

C(8,20) = 480$

C(24,8) = 504$

Hence, the minimum cost would be 480$ when Inna works for 8 hours and Jim works for 20 hours.

The attached image shows the graph.

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Answer:

10 inches.

Step-by-step explanation:

If 1 inch represents 150 miles, and there are 1500 miles covered by the map, then the length of the highway on the map is 10 inches.

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The moon is 384,403 km from the Earth. Estimate how many quarters laid end to end it would take to reach the moon if a quarter h
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$16.96  16 times 6% is .96
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You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Makovka662 [10]

Answer:

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

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Mr. Petrov was trying to choose between two different plans for dollhouses for his daughter. Both dollhouses have a rectangular
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Answer:

(4). The space inside dollhouse 1 is 24 inches cubed greater than the space inside dollhouse 2.

As the correct equation should add up to 192 dolls house 1 and 168 for dolls house 2; 192 -168 = 24 cubed inches.

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Dolls house 2 = should be V= 6(6)5 - one third of 6(6) = 180-12 =168 cubed inches not 188 as shown in equation 2

Where all the other listed answers in question are incorrect as they add up to 334 or 188.

Step-by-step explanation:

dh1+2 rectangle = 6 x 5 x 4 = 120

Volume of triangle

V = 0.5 X b X a X h. = 0.5 x 6 x 6 x 4 = 72sq^3 + 120-sq^3 = 192sq^3

Volume of the Pyramid/rectangle dh = lwh/3

= 6x6x4=144/3=48sq^3 +  120sq^3= V = 168sq^3

Both A + B = V= 192sq^3, B=168sq^3

To calculate the volume of a triangular prism, measure the width and height of a triangular base, then multiply the base by the height by 1/2 to determine the triangle's area. Next, measure the height of the triangular prism and multiply this by the triangle's area to get the volume.

To calculate the volume of a pyramid with a rectangular base, find the length and width of the base, then multiple those numbers together to determine the area of the base. Next, multiply the area of the base by the height of the pyramid. Take that result and divide it by 3 to calculate the pyramid's volume

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Answer:

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The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

Step-by-step explanation:

we have

f(x)=x^{2}

This is a vertical parabola open upward

The vertex is a minimum

The vertex is the origin (0,0)

g(x)=-5x^{2}+100x-450

This is a vertical parabola open downward

The vertex is a maximum

The first thing to note is that fx) is a parabola that opens up and g(x) opens down, so a reflection across the x-axis must have been applied.

Find the vertex of g(x)

Convert to vertex form

g(x)=-5x^{2}+100x-450

Complete the square

g(x)=-5(x^{2}-20x)-450

g(x)=-5(x^{2}-20x+100)-450+500

g(x)=-5(x^{2}-20x+100)+50

g(x)=-5(x-10)^{2}+50

The vertex is the point (10,50)

so

To translate the vertex of (0,0) to (10,50)

The rule of the translation is

(x,y) ------> (x+10,y+50)

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The transformations are

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The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

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