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Crazy boy [7]
2 years ago
13

the richmond park gamekeeper wanted to know how many deer were in the park . he caught 90 of them and put a small tag round a ho

of of each of them . He then let the deer go back into the park the next week, the gamekeeper caught 70 deer. 10 of the deer had a tag around their hooves a) using this information, what estimate did the gamekeeper make for how many deer were in the park? b) write down one assumption he made

Mathematics
1 answer:
Alenkasestr [34]2 years ago
5 0

Answer:

a. Since 10 out of 70 had a tag we can write the ratio 10:70. We need to solve for x in 90:x. x = 630 so the answer is 630.

b. An assumption he could have made is that the number of deer that had a tag and the total amount of deer were directly proportional.

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Step-by-step explanation:

a) 7!

If there are no restrictions, answer is 7! as it is the permutation of all animals.

b) 4! x 3!

As cats are 6 and Dogs are 5, thus 1st and last must be cats in order to have alternate arrangements. Therefore the only choices are the order of the cats among  themselves and the order of the dogs among themselves. There are 4! permutations of the cats and 3! permutations of the dogs, so there are a total of 4! x 3! possible arrangements of the suites.

c) 3! x 5!

There are 3! possible arrangements of  the dogs among themselves. Now, if we consider the dogs as  one ”object” together, then we can think of arranging the 4 cats  together with this 1 additional object. There are 5! such arrangements possible, so there are a total of 3! · 5! possible arrangements of the suites.

d) 2 x 4! x 3!

As required that all the cats must be together and all the dogs must be together, either the cats are all  before the dogs or the dogs are all before the cats. There are two possible arrangements thus two times of both possibilities is the answer i.e.  2 x 4! x 3!

3 0
2 years ago
Consider the initial value problem y′+4y=48t,y(0)=9. y′+4y=48t,y(0)=9. Take the Laplace transform of both sides of the given dif
Nadusha1986 [10]

Answer:

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L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}

Now if we take inverse we get y(t) the solution

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8 0
2 years ago
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yKpoI14uk [10]

Answer:

21/20

Step-by-step explanation:

a) One hour is equivalent to 60 minutes.

So we can multiply 50 minutes by the fraction \frac{1 hour}{60 minutes}, so we could convert 50 minutes to hours.

It is:

50 minutes * \frac{1 hour}{60 minutes}=\frac{50}{60}hours

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Answer:

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So the correct answer is:

C. 67.5 to 72.

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