There is little information please state more points.
Mike tosses 70%
Ike tosses 67%
Both tosses 50%
<span>Which of the following is closest to the probability that Ike's proportion is ringers is higher than Mike's for those tosses?
</span>
P(m) = 70/100
P(i) = 67/100
P(b) = 50/100
= P(b) * P(i)
= 50/100 * 67/100
= 0.335
The correct answer is letter D) 0.3745.
Answer:
See the solutions below
Step-by-step explanation:
Given data
Distance = 24.6km
in meters= 24.6*1000= 24600m
time= 30 minutes
in seconds= 30*60= 1800
int hours= 0.5 hour
speed of the particle in
(i) km/h= 24.6/0.5= 49.2 km/h
(ii) m/s.= 24600/ 1800= 13.66 m/s
Answer:
a). x = 11
b). m∠DMC = 39°
c). m∠MAD = 66°
d). m∠ADM = 36°
e). m∠ADC = 18°
Step-by-step explanation:
a). In the figure attached,
m∠AMC = 3x + 6
and m∠DMC = 6x - 49
Since "in-center" of a triangle is a points where the bisectors of internal angles meet.
Therefore, MC is the angle bisector of angle AMD.
and m∠AMC ≅ m∠DMC
3x + 6 = 8x - 49
8x - 3x = 49 + 6
5x = 55
x = 11
b). m∠DMC = 8x - 49
= (8 × 11) - 49
= 88 - 49
= 39°
c). m∠MAD = 2(m∠DAC)
= 2(30)°
= 60°
d). Since, m∠AMD + m∠ADM + m∠MAD = 180°
2(39)° + m∠ADM + 66° = 180°
78° + m∠ADM + 66° = 180°
m∠ADM = 180° - 144°
= 36°
e). m∠ADC = 
= 
= 18°