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2 years ago

Lyn drew this bar model to solve a problem. What operation should she use to find the unknown number .

1 answer:

7 0

It appears that you have overlooked the set of options for this problem. To solve the problem, Lynn Drew ought to use the operation of ADDITION to find the unknown number. Given that there are 90 flowers and 54 flowers, the unknown number that you are looking for would be 144.

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From 1994 to 1995 the sales of a book decreased by 80%. If the sales in 1996 for the same as in 1994, By what percent did the in

zheka24 [161]

Answer:

400%

Step-by-step explanation:

Let the sales be "100" in 1994

Since, it decreased 80%, the sales was:

80% = 80/100 = 0.8

0.8 * 100 = 80 (decreased by 80)

So, it was

Sales in 1995: 100 - 80 = 20

Sales in 1996 was same as in 1994, so that's 100

Thus,

Sales in 1994: 100

Sales in 1995: 20

Sales in 1996: 100

We need to find percentage increase form 1995 to 1996, that is what percentage increase is from 20 to 100?

We will use the formula:

$\frac{New-Old}{Old}*100$

Where

New is 100

Old is 20

SO, we have:

$\frac{New-Old}{Old}*100\\=\frac{100-20}{20}*100\\=4*100\\=400$

So, it increased by 400%

3 0

2 years ago

What is the weight in grams of a liquid that exactly fills 163.5 ml container if the density of the liquid is .492 G / milliliIt

fenix001 [56]

density= mass/volume 0.492=mass/163.5 mass=0.492*163.5 mass =80.448gram. Hope this helps!

8 0

2 years ago

How many ML are equal to 4.567x10^4

Phoenix [80]

Answer:45670 ML

Step-by-step explanation:

Sorry if wrong.

7 0

2 years ago

If you were to make a scatter plot of data, you would be able to determine the line of best fit. Using the regression equation y

VMariaS [17]

Answer:

Option B. is correct

Step-by-step explanation:

Given: The regression equation is y = 1.73 x + 0.39

To find: number of representatives for Oregon, which has a population of about 3.3 million

Solution:

The regression equation determined the specific relationship between a dependent variable and one or more independent variables.

To find number of representatives for Oregon, which has a population of about 3.3 million, put $x=3.3$ in the regression equation is y = 1.73 x + 0.39

$y = 1.73 x + 0.39\\y = 1.73 (3.3) + 0.39\\=5.709+0.39\\=6.099\\\approx 6$

So, 6 representatives for Oregon has a population of about 3.3 million

Option B. is correct

6 0

2 years ago

Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first

BaLLatris [955]

Answer:

$\cos(x+y)$ goes with $-\frac{\sqrt{6}+\sqrt{2}}{4}$

$\sin(x+y)$ goes with $\frac{\sqrt{6}-\sqrt{2}}{4}$

$\tan(x+y)$ goes with $\sqrt{3}-2$

Step-by-step explanation:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

We are given:

$\sin(x)=\frac{\sqrt{2}}{2}$ which if we look at the unit circle we should see

$\cos(x)=\frac{\sqrt{2}}{2}$ .

We are also given:

$\cos(y)=\frac{-1}{2}$ which if we look the unit circle we should see

$\sin(y)=\frac{\sqrt{3}}{2}$ .

Apply both of these given to:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}$

$\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}$

$\frac{-\sqrt{2}-\sqrt{6}}{4}$

$-\frac{\sqrt{6}+\sqrt{2}}{4}$

Apply both of the givens to:

$\sin(x+y)$

$\sin(x)\cos(y)+\sin(y)\cos(x)$ by addition identity for sine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}$

$\frac{-\sqrt{2}+\sqrt{6}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$

Now I'm going to apply what 2 things we got previously to:

$\tan(x+y)$

$\frac{\sin(x+y)}{\cos(x+y)}$ by quotient identity for tangent

$\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}$

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}$

Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}$

$-\frac{6-\sqrt{2}\sqrt{6}-\sqrt{2}\sqrt{6}+2}{6-2}$

$-\frac{8-2\sqrt{12}}{4}$

There is a perfect square in 12, 4.

$-\frac{8-2\sqrt{4}\sqrt{3}}{4}$

$-\frac{8-2(2)\sqrt{3}}{4}$

$-\frac{8-4\sqrt{3}}{4}$

Divide top and bottom by 4 to reduce fraction:

$-\frac{2-\sqrt{3}}{1}$

$-(2-\sqrt{3})$

Distribute:

$\sqrt{3}-2$

6 0

2 years ago