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Rina8888 [55]
2 years ago
12

A frequency distribution lists the _________ of occurrences of each category of​ data, while a relative frequency distribution l

ists the __________ type proportion number of occurrences of each category of data.
Mathematics
1 answer:
Tanzania [10]2 years ago
8 0

Answer:

A frequency distribution lists the<u> number</u> of occurrences of each category of​ data, while a relative frequency distribution lists the <u>proportion</u> of occurrences of each category of data.

Explanation:

A "frequency distribution" is one of the ways in organizing a data, either by <em>listing the information, putting them in a table or showing them in a graph.</em> The items in the list (distinct values) are then counted when it comes to the number of times they've occurred.

Thus, this explains the first answer, "number."

On the other hand, a "relative frequency distribution" refers to the proportion of the overall number of observations in a particular category.  <u>You can get this by dividing each frequency with the total number of data in a sample.</u>

Thus, this explains the second answer, "proportion."

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Consider the function represented be the table. What is f(0)?
mamaluj [8]

9514 1404 393

Answer:

  6

Step-by-step explanation:

The value of f(x) for x=0 is f(0). The first line of the table tells you that value is 6.

  f(0) = 6

7 0
2 years ago
Ms. tucker travels through two intersections with traffic lights as she drives to the market. the traffic lights operate indepen
sergij07 [2.7K]
The probability of two independent events occurring one after the another is the product of these probabilities, i.e. P(red1,red2)=0.22

We have given that the probability of the first being red and the second not being red is 0.33,

The probability of the first light being red is P(red1)=0.33+0.22=0.55. 

And we know that these events are independent, then 

P(red1)*P(red2)=P(red1,red2)
0.55*P(red2)=0.22
P(red2)=0.4
4 0
2 years ago
2. A boy and his father played 26 games of checkers. For every game the boy lost, he gave his father 5 cents. For every game the
trasher [3.6K]

Answer: the boy won 10 games

Step-by-step explanation:

Let's call B as the number of games won by the boy, and F as the number of games won by the father.

We know that, there is a total of 26 games:

B + F = 26.

We know that in each game won by the boy, he wins 8 cents, for every game that the father wins, the boy losses 5 cents, and we know that at the end of the 26 games, the boy did not win or lose any money, so we have:

B*8 + F*(-5) = 0.

Then we have a system of equations:

B + F = 26

8*B - 5*F = 0.

The first step is isolating one of the variables. Let's start isolating F in the first equation:

B + F = 26

F = 26 - B.

Now we can replace this in the second equation:

8*B - 5*F = 0

8*B - 5*(26 - B) = 0

8*B + 5*B - 5*26 = 0

13*B = 5*26

B = 5*26/13 = 5*2 = 10

So the boy won 10 games (then the father won the other 16 games)

7 0
2 years ago
The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 30.05 inches

           \sigma   = standard deviation = 0.2 inches

             n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z < 3) = 0.99865

 P(X bar <= 30.25) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

                                                                                       = 0.0214

                                       

7 0
2 years ago
A student writes the equation for a line that has a slope of -6 and passes through the point (2, –8). y -(-8) = -6(x - 2) y -(-8
Mice21 [21]
Y - (-8) = -6 (x-2) is correct everything else is not
y + 8 = -6x + 12
y +:8 - 8 = -6x + 12 - 8
y = -6x + 4 is slope intercept form
6 0
2 years ago
Read 2 more answers
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