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2 years ago

Sal exercised by stretching and jogging 5 days last week.

1 answer:

4 0

So sal stretched for about 5 min. each day in 5 days and he jogged for about 43 min ..how??
I divided 215 to 5 and I got 43 min. and how did I get 215 well 240 minus 25 min is 215

and elena she stretches for 75 min in the whole 5 days total and 300 minus 75 is 225. then 225 divided by 15 is 15

Sam jogged for 43 min a day and elena jogged for 15 min a day
I hope this helps :)

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You need to write an essay that has at least 500 words you have written 285 words so far right and solve an inequality that Reec

andrezito [222]

Answer:

The minimum number of words left to write is 215

Step-by-step explanation:

Let

w -----> the number of words left to write

we know that

The number of words left to write plus the words written so far must be greater than or equal to 500 words

Remember that the word "at least" means "greater than or equal to"

$w+285\geq 500$

Solve for w

Subtract 285 both sides

$w\geq 500-285\\w\geq 215$

The minimum number of words left to write is 215

3 0

2 years ago

Sunita bought a 10 kg box of grapes from the market. She gave 3 1/2 kg of her grapes to her friend Reena and 2 1/4 kg to Anita.

kirill115 [55]

Answer:

17/4 kg

Step-by-step explanation:

Sunita has = 10kg of grapes

Quantity given out :

To Reena =3 1/2

7/2 kg

To Anita =2 1/4

9/4 kg

Total quantity of grape given out

7/2+9/4

(14+9)/4

23/4

Quantity left after giving out = Total quantity of grape before giving out minus quantity of grape given out

10/1 - 23/4

40-23)/4

= 17/4 or 4 1/4

Hence, she has 17/4 kg of grape left with her

5 0

2 years ago

The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between x(height) and y(arm span) is sho

abruzzese [7]

Answer:

27.385 cm longer would we expect Mike's arm span to be than George's.

Step-by-step explanation:

We have to find how many centimeters longer would we expect Mike's arm span to be than George's using the equation:

y= 4.5x + 0.977 x

where y= arm span

and x= height

Given:

Mike's height=x = 175 cm

so Mike's arm span= y= 4.5 x + 0.977 x

= 4.5* (175) + 0.977* (175)

= 787.5 + 170.975

= 958.475 cm

George's height = x = 170 cm

so George's arm span= y= 4.5 x + 0.977 x

= 4.5* (170) + 0.977* (170)

= 765 + 166.09

= 931.09 cm

Mike's arm span longer than George's = Mike's arm span - George's arm span

= 958.475 - 931.09

= 27.385 cm.

8 0

2 years ago

Jenny’s mother is 5 years older than twice Jenny's age. The sum of their ages is 62 years. This is represented by the equation x

Salsk061 [2.6K]

Answer:

Jenny´s age is 19 and her mother is 43.

Step-by-step explanation:

1. Plug in the first value of the set

41 is different from 62, so Jenny isn´t 12 years old.

2. Plug in the second value of the set

50 is different from 62, so Jenny isn´t 15 years old.

3. Plug in the third value of the set

59 is different from 62, so Jenny isn´t 18 years old.

4. Plug in the fourth value of the set

Therefore Jenny´s 19 years old.

5. Calculate Jenny´s mother age:

As the sum of their ages is 62 ages, we have the following equation

where

x=Jenny´s age

y=Jenny´s mother age

Therefore Jenny's mother age is 43 years old.

pls mark me brainliest

8 0

2 years ago

The following histogram presents the amounts of silver (in parts per million) found in a sample of rocks. One rectangle from the

gladu [14]

Answer:

The height of the missing rectangle is 0.15

Explanation:

The image attached has the mentioned histogram.

Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.

Only the rectangle for the class [3,4] is missing.

The height of each rectangle is the relative frequency of the corresponding class.

The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.

In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.

1. Sum of the known relative frequencies:

0.2 + 0.3 + 0.15 + 0.1 + 0.1 = 0.85

2. Missing frequency:

1 - 0.85 = 0.15

3. Conclusion:

The height of the missing rectangle is 0.15

4 0

2 years ago