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erma4kov [3.2K]
2 years ago
8

Which image (A'B'C'D') of ABCD cannot be produced using only reflections? A. B. C. D.

Mathematics
1 answer:
liberstina [14]2 years ago
3 0

Answer:

the answer is D

Step-by-step explanation:

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Guided Practice
KATRIN_1 [288]

Answer:

i would think its C

Step-by-step explanation:

the other options dont make sense lol

hope this is correct and helps :)

5 0
2 years ago
Read 2 more answers
If this particular arithmetic sequence, a7=34 and a15=74. What is the value of a21
Ilya [14]
This is an arithmetic sequence, meaning, to get the next term, you simply add some value to the current one, namely the "common difference" "d".

now, we know the 17th term is 34, let's go to the 15term then

34 + d
34 + d + d
34 + d + d + d
34 + d + d + d + d
34 + d + d + d + d + d
34 + d + d + d + d + d + d
34 + d + d + d + d + d + d + d
34 + d + d + d + d + d + d + d + d

now, notice, we got to the 15th term, which is 34  + d + d + d + d + d + d + d + d, or namely 34 + 8d, it just so happen we know is 74, therefore,

\bf 34+8d=74\implies 8d=40\implies d=\cfrac{40}{8}\implies \boxed{d=5}

ok, now that we know what the common difference is, let's find the first term in the sequence using the 7th term of 34,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=7\\
d=5\\
a_7=34
\end{cases}
\\\\\\
a_7=a_1+(7-1)5\implies 34=a_1+(7-1)5
\\\\\\
34=a_1+30\implies \boxed{4=a_1}

and now let's use those 2 found folks, to get the 21st term,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=4\\
d=5\\
n=21
\end{cases}
\\\\\\
a_{21}=4+(21-1)5\implies a_{21}=4+100\implies a_{21}=104
3 0
2 years ago
Which point shows the location of 5 – 2i on the complex plane below? On a coordinate plane, points A, B, C, and D are shown. Poi
Romashka-Z-Leto [24]

Answer:

The Point C shows the location of 5-2i in the complex plane: 5 points to the right of the origin and 2 points down from the origin.

Step-by-step explanation:

We have the complex number 5-2i and we have to show the location of the point that represents that number in the complex plane

In the complex plane the real numbers are located in the horizontal axis, increasing to the right. The positives real numbers are at the right of the origin and the negatives to the left.

The complex numbers are located in the vertical axis, with the positives over the origin and the negatives below the origin.

This complex number 5-2i is the sum of a real part (5) and a imaginary part (-2i), so the point will be 5 units rigth on the horizontal axis (for the real part) and 2 units down in the vertical axis (for the imaginary part).

8 0
2 years ago
Read 2 more answers
Harmony earns a \$42{,}000$42,000dollar sign, 42, comma, 000 salary in the first year of her career. Each year, she gets a 4\%4%
saveliy_v [14]

Answer:

FV(n)=42,000(1.04)^n

Step-by-step explanation:

FV=PV(1+r/n)^nt

Where

FV=future value

PV=present value

r=interest rate

n=number of periods

t=time (years)

PV=42,000

r=4%=0.04

n=1

t=n

FV(n)=p(1+r/n)^nt

=42,000(1+0.04/1)^1*n

=420000(1+0.04)^n

=42,000(1.04)^n

FV(n)=42,000(1.04)^n

7 0
2 years ago
Use the following compound interest formula to complete the problem.
alexdok [17]

Card P's balance increased by $3.43 more than Card Q's balance. The accumulated total on Card P over the 4 years is $1080.70 and the accumulated total of Card Q is $1,206.28. Based on the principal outlay however, Card P would have netted a higher interest over Card Q when the principal is subtracted from the accumulated value. (For eg. Card P accumulated value $1080.70 less Principal $726.19 equals $354.51).The interests over the 4 years period would be $354.51 and $351.08 respectively, hence Card P having an increase in balance of $3.43 over Card Q.

5 0
2 years ago
Read 2 more answers
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