Answer:
∅1=15°,∅2=75°,∅3=105°,∅4=165°,∅5=195°,∅6=255°,∅7=285°,
∅8=345°
Step-by-step explanation:
Data
r = 8 sin(2θ), r = 4 and r=4
iqualiting; 8.sin(2∅)=4; sin(2∅)=1/2, 2∅=asin(1/2), 2∅=30°, ∅=15°
according the graph 2, the cut points are:
I quadrant:
0+15° = 15°
90°-15°=75°
II quadrant:
90°+15°=105°
180°-15°=165°
III quadrant:
180°+15°=195°
270°-15°=255°
IV quadrant:
270°+15°=285°
360°-15°=345°
No intersection whit the pole (0)
Answer:
C. JKM is not a right triangle because KM ≠ 15.3.
Step-by-step explanation:
We can see from our diagram that triangle JKM is divided into right triangles JLM and JLK.
In order to triangle JKM be a right triangle
.
We will find length of side KM using our right triangles JLM and JLK as
.
Using Pythagorean theorem in triangle JLM we will get,


Now let us find length of side KL.


Now let us find length of KM by adding lengths of KL and LM.

Now let us find whether JKM is right triangle or not using Pythagorean theorem.



Upon taking square root of both sides of equation we will get,
We have seen that KM equals 18.2 and in order to JKM be a right triangle KM must be equal to 15.3, therefore, JKM is not a right triangle and option C is the correct choice.
The formula for the area of a circle is PI x radius^2.
To find the area of the sector, you would multiply the area by the ratio of the the sector angle over 360.
The formula would become PI x r^2 x 30/360.
The 2nd choice is correct.
15500 times 0.37 is 5735.
$5735
The 11% statement is extra information.