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allsm [11]
2 years ago
11

It is desired to test H0: μ = 55 against H1: μ < 55 using α = 0.10. The population in question is normally distributed with a

standard deviation of 20. A random sample of 64 will be drawn from this population. If μ is really equal to 50, what is the probability that the hypothesis test would lead the investigator to commit a Type II error?
Mathematics
1 answer:
patriot [66]2 years ago
3 0

Answer:

Step-by-step explaation: 42% of 85 is what number

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Shayna enlarged a square photo by adding 10 inches to each side so it could be seen on a large poster. The area of the enlarged
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The area of a square is expressed as the length of the side to the power of two, A = s^2. We were given the area of the enlarged photo which is 256 in^2. Also, it was stated that the length of the enlarged photo is the length of the original photo plus ten inches. So, from these statements we can make an equation to solve for x which represents the length of the original photo.

A = s^2
where s = (x+10)
A = (x+10)^2 = 256
Solving for x,
x= 6 in.

The dimensions of the original photo is 6 x 6.
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2 years ago
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A volunteer is organizing the snacks at a concession stand and notices the ratio is sweet snacks to salty snacks is 5:1. If ther
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100 sweet snack, if it is 5:1 ratio than there’s 5 times the amount of salty snacks
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2 years ago
Given triangle GHJ, the measure of angle G equals 110°, the measure of angle J equals 40°, and the measure of angle H equals 30°
tester [92]

Answer:

Since angle G is  

✔ the largest

 angle, the opposite side, JH, is  

✔ the longest side

. The order of the side lengths from longest to shortest is  

✔ HJ, GH, and GJ

.

Step-by-step explanation:

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1 year ago
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On september 8, 2004, the genesis spacecraft crashed in the utah desert because its parachute did not open. the 210-kg capsule h
maw [93]
311km/h = 86.389 m/s 
<span>Initial KE </span>
<span>= 0.5 * 210 * 86.389^2 J </span>

<span>work done by force of ground </span>
<span>= F * 0.81 J </span>

<span>0.5 * 210 * 86.389^2 = 0.81 F </span>

<span>F = 967433.58 N </span>

<span>capsule's weight W= 210 * 9.81 = 2060.1 N </span>

<span>F = 469.6 times capsule weight ---answer</span>
6 0
2 years ago
A rectangular piece of land is 40m long and 25m wide. A path of uniform width and 426 m^2 area sorrounds
fredd [130]

Answer:

Width of the uniform path that surrounds the piece of land = 3 m

Step-by-step explanation:

Let the width of the path that surrounds the piece of land be x.

The situation described is sketched in the attached image to this solution.

The dimension of the Length of the piece of land including the uniform path that surrounds it = (40 + 2x) m

The Breadth of the piece of land including the uniform path that surrounds it = (25 + 2x) m

The area of the piece of land including the uniform path that surrounds it

= (Area of the piece of land) + (Area of the uniform path that surrounds it)

Area of the piece of land = Length × Breadth = 40 × 25 = 1000 m²

Area of the uniform path that surrounds it = 426 m² (Given in the question)

The area of the piece of land including the uniform path that surrounds it = 1000 + 426 = 1426 m²

But the area of the piece of land including the uniform path that surrounds it is also

= (Length of the piece of land including the uniform path that surrounds it) × (Breadth of the piece of land including the uniform path that surrounds it

= (40 + 2x) + (25 + 2x)

= 1000 + 80x + 50x + 4x²

= (4x² + 130x + 1000) m²

Equation these 2 areas

4x² + 130x + 1000 = 1426

4x² + 130x - 426 = 0

Solving the quadratic equation

x = 3 or -35.5

Since the width cannot be negative,

x = 3 m

Hope this Helps!!!

7 0
2 years ago
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