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lana66690 [7]
2 years ago
6

A food packet is dropped from a helicopter and is modeled by the function f(x) = -16x2 + 14400. The graph below shows the height

f(x), in feet, of the food packet at different times x, in seconds:
Use the graph to determine the reasonable domain of f(x) based on the context.

a.) 0 _ x _ 30

b.)0 _ x _ 14400

c.) -30 _ x _ 30

d.) All real numbers

Mathematics
2 answers:
yulyashka [42]2 years ago
8 0

Answer:

The reasonable domain is 0\leq x\leq 30.

Step-by-step explanation:

The given function is

f(x)=-16x^2+14400

Where, f(x) is height (in feet) of the food packet and x is time( in seconds).

Since the leading coefficient is negative, therefore it is an downward parabola.

The time is always positive value, therefore the domain of f(x) must be greater than or equal to zero.

0\let x                                    .... (1)

The given equation can be written as

f(x)=-16(x^2-900)

f(x)=-16(x^2-(30)^2)

f(x)=-16(x-30)(x+30)

Equate each factor equal to 0, to find the x-intercepts.

x=30,-30

From the graph of f(x) is noticed that the x-intercepts are -30 and 30. Before -30 and after 30 the graph of f(x) gives negative values. Therefore the domain must be lies between -30 to 30.

-30\let x\leq 30                                    .... (2)

From (1) and (2), we get

0\leq x\leq 30

Therefore the reasonable domain is 0\leq x\leq 30.

Elis [28]2 years ago
6 0
From the graph, the domain is 0 ≤ x ≤ 30
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Answer:

2/3

Step-by-step explanation:

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2 years ago
A university is trying to determine what price to charge for tickets to football games. At a price of ​$ per​ ticket, attendance
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This question is incomplete, the complete question is;

A university is trying to determine what price to charge for tickets to football games. At a price of ​$24 per​ ticket, attendance averages 40,000 people per game. Every decrease of ​$4 adds 10,000 people to the average number. Every person at the game spends an average of ​$4 on concessions. What price per ticket should be charged in order to maximize​ revenue? How many people will attend at that​ price?

Answer:

a) price per ticket = $18

b) 55,000 will attend at that price

Step-by-step explanation:

Given that;

price of ticket = $24

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every decrease of $4 adds 10,000 people

for $1 adds 2,500 people

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Revenue function = people × cost + people × 4

so

R(x) = (40000 + 2500x)(24 - x) + (40000 + 2500x)4

R(x) = 960,000 - 40000x + 60000x - 2500x² + 160,000 + 10000x

R(x) = 1120000 + 30000x - 2500x²

R(x) = -2500x² + 30000x + 1120000

now for maximum revenue; R'(x) is to zero

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R'(x) = d/dx(  -2500x² + 30000x + 1120000 ) = 0

⇒ -5000x + 30000 + 0 = 0

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x = 30000 / 5000

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∴ Revenue is maximum at x = 6

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= 40000 + (2500 × 6)

= 40000 + 15,000

= 55,000

Therefore, 55,000 will attend at that price

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1 year ago
The commission earned on the sale of a car can be represented by the equation c(p)=250+0.02p where c represents the commission a
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Answer:

1) His total commission is $1,234.3

2) The purchase of the car is $24,790.

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1) 21640*0.02= 432.8+ 250= 682.8

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Answer:

Step-by-step explanation:

Hello!

To test the claim that eating a healthy breakfast improves the performance of students on their test a math teacher randomly asked 46 students what did they have for breakfast before they took the final exam and classified them as:

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X₁: Number of students that ate a healthy breakfast before the exam and earned 80% or higher.

n₁= 26

<u>Group 2: </u>Did not eat healthy breakfast

X₂: Number of students that did not eat a healthy breakfast before the exam and earned 80% or higher.

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After the test she counted the number of students that got 80% or more in the test for each group obtaining the following sample proportions:

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The p-value: 0.2514 is greater than the significance level 0.05, the test is not significant.

At a 5% significance level you can conclude that the population proportion of math students that obtained at least 80% in the test and had a healthy breakfast is equal or less than the population proportion of math students that obtained at least 80% in the test and didn't have a healthy breakfast.

So having a healthy breakfast doesn't seem to improve the grades of students.

I hope this helps!

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