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S_A_V [24]
1 year ago
12

Louisa has a goal of collecting 100 pounds of dog food for a local shelter. She records how many pounds of food she collects eac

h week.
Week
Pounds Collected
1
20.5
2
18 and three-fourths
3
32.75

How many more pounds of dog food does Louisa need to reach her goal?
How many more pounds of dog food does Louisa need to reach her goal?
Mathematics
2 answers:
Anit [1.1K]1 year ago
8 0

Answer:

28 more pouds of dog food

Step-by-step explanation:

Daniel [21]1 year ago
6 0

Answer:

28 or C

Step-by-step explanation:

Got it right on my test.

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Jeanie has $500 to spend on dance lessons. There is a $50 one-time registration fee, and the lessons cost $35 each. How many les
Sindrei [870]
Jeanie can take 12 lessons.

500-50=450
450/35=12.86
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2 years ago
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When does a payday loan typically mature?
marin [14]

Payday loans which are also called short term loans or sometimes referred to as cash advances. These types of loans are based upon the borrower’s employment payroll records. Since this is based upon the payroll records of the borrower that means that it will mature after the borrower’s next pay check.  So the answer to the question is:

C. After the borrower’s next paycheck.

6 0
1 year ago
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plz help whats the answer to this question !!! calculate the mass of a gold bar that is 18.00cm long, 9.21cm wide, and 4.45cm hi
erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar = length \times width\times height

Plugging the values in the equation we get,

Volume of the gold bar =18.00 \times 9.21 \times 4.45= 737.721cm^3

Now that we have the volume we can find the mass by using the formula,

Mass= density \times volume

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

Mass = 19.32\times 737.721=14252.769 grams

So, the mass of the gold bar is 14252.769 grams

7 0
2 years ago
Find all x in set of real numbers R Superscript 4 that are mapped into the zero vector by the transformation Bold x maps to Uppe
sukhopar [10]

Answer:

 x_3 = \left[\begin{array}{c}4&3&1\\0\end{array}\right]

Step-by-step explanation:

According to the given situation, The computation of all x in a set of a real number is shown below:

First we have to determine the \bar x so that A \bar x = 0

\left[\begin{array}{cccc}1&-3&5&-5\\0&1&-3&5\\2&-4&4&-4\end{array}\right]

Now the augmented matrix is

\left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\2&-4&4&-4\ |\ 0\end{array}\right]

After this, we decrease this to reduce the formation of the row echelon

R_3 = R_3 -2R_1 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\0&2&-6&6\ |\ 0\end{array}\right]

R_3 = R_3 -2R_2 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\0&0&0&-4\ |\ 0\end{array}\right]

R_2 = 4R_2 +5R_3 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&4&-12&0\ |\ 0\\0&0&0&-4\ |\ 0\end{array}\right]

R_2 = \frac{R_2}{4},  R_3 = \frac{R_3}{-4}  \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&1\ |\ 0\end{array}\right]

R_1 = R_1 +3 R_2 \rightarrow \left[\begin{array}{cccc}1&0&-4&-5\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&-1\ |\ 0\end{array}\right]

R_1 = R_1 +5 R_3 \rightarrow \left[\begin{array}{cccc}1&0&-4&0\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&-1\ |\ 0\end{array}\right]

= x_1 - 4x_3 = 0\\\\x_1 = 4x_3\\\\x_2 - 3x_3 = 0\\\\ x_2 = 3x_3\\\\x_4 = 0

x = \left[\begin{array}{c}4x_3&3x_3&x_3\\0\end{array}\right] \\\\ x_3 = \left[\begin{array}{c}4&3&1\\0\end{array}\right]

By applying the above matrix, we can easily reach an answer

5 0
1 year ago
Yoku is putting on sunscreen. He uses 2\text{ ml}2 ml2, start text, space, m, l, end text to cover 50\text{ cm}^250 cm 2 50, sta
Kaylis [27]

Answer:

13 Millilitres.

Step-by-step explanation:

Yoku uses 2ml to cover 50cm^2 of his skin.

He wants to know how many millilitres of sunscreen he will need to cover 325cm^2 of his body.

If Yoku covers 50cm^2 of his skin will 2ml

He will cover 1cm^2 of his skin with \frac{2}{50}ml of sunscreen.

Therefore:

To cover 325cm^2 of his body, he will use:

\frac{2}{50} X 325 ml\\=13ml

he would require 13 Millilitres.

7 0
2 years ago
Read 2 more answers
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