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zloy xaker [14]
2 years ago
15

Assume 6 in every 2000 students at the local community college have to quit due to serious health issues. An insurance company o

ffers them a ​$10,000 policy for ​$60 a year. What is the amount the insurance company should expect to make on average on every student that​ pays?
Mathematics
1 answer:
Alexus [3.1K]2 years ago
7 0
Given:

6 out of 2000 students quit community college due to serious health issues.
$10,000 insurance company offer
$60 per year

Based on the data, there are 6 students who will be given the $10,000 insurance per year. So they need

6 * 10,000 = $60,000 to make a break-even on their insurance offer

If a student pays $60 per year, they should have

$60,000 / $60 = 1,000 students who will pay per year to reach the break-even mark of their investment. If the number of students will exceed 1,000, the company will begin to earn. 
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During his last 5 jobs, an electrician used the following amounts of cable:
ella [17]

The total amount of cable used is 47.4m

<u>Explanation:</u>

Given:

Amounts of cable used that has to be rounded off to 1 decimal place:

12.995 m  ≈ 13.0 m

7.505 m  ≈ 7.5m

10.08 m  ≈ 10.1 m

6.95 m  ≈ 7.0 m

9.75 m ≈ 9.8 m

Total amount of cable used = 13m + 7.5m + 10.1m + 7m + 9.8m

                                              = 47.4m

Therefore, total amount of cable used is 47.4m

7 0
2 years ago
Compute i^1+i^2+i^3....i^99+i^100
fgiga [73]

Good morning ☕️

Answer:

<h3>i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰ = 0</h3>

Step-by-step explanation:

Consider the sum S = i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰

S =  i¹ +  i² +  i³ + . . . + i⁹⁹  +  i¹⁰⁰

S = a₁ + a₂ + a₃ +. . . + a₉₉ + a₁₀₀

then, S is the sum of 100 consecutive terms of a geometric sequence (an)

where the first term a1 = i¹ = i  and the common ratio = i

FORMULA:______________________

S=(term1)*\frac{1-(common.ratio)^{number.of.terms}}{1-(common.ratio)}

_______________________________

then

S=i*\frac{1-i^{100} }{1-i}

or i¹⁰⁰ = (i⁴)²⁵ = 1²⁵ = 1  (we know that i⁴ = 1)

Hence

S = 0

7 0
2 years ago
There are 28.35 grams in an ounce and 2.21 pounds in a kilogram. Miriam converted 7 kilograms to ounces, but her answer is not c
sergejj [24]

Answer: OPTION C.

Step-by-step explanation:

For this exercise it is important to remember the following:

1\ kilogram=1,000\ grams

Knowing this and based on the information provided in the exercise, you can make the conversion from kilograms to ounces. This is:

(7\ Kg)(\frac{1,000\ gr}{1\ Kg})(\frac{1\ oz}{28.35\ gr})=246.913\ oz

According to the exercise, Miriam's procedure was:

 (7\ Kg)(\frac{1,000\ gr}{1\ Kg})(\frac{28.35\ gr}{1\ oz})= 198,450\ oz

So you can identify that she made a mistake.

Notice that:

1. Miriaim multiplied correctly.

2. Butt the third fraction should be \frac{1\ oz}{28.35\ gr} and not \frac{28.35\ gr}{1\ oz}.

5 0
2 years ago
Read 2 more answers
Aro diagrams his river rafting trip, estimating the time it will take him to paddle upstream against the current, and then back
eduard

Answer:

Upstream

5.2=(x-y)5

Downstream

5.2=(x+y)2.5

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Juana compró una camioneta 4x4 a S/ 42 000; además, sabe que la camioneta se depreciará (bajará su precio) en forma lineal duran
prohojiy [21]

Answer:

Una relación lineal es de la forma:

y = a*x + b.

donde a es la pendiente y b es la ordenada al origen.

en este caso, y es el precio de la camioneta, x es el numero de años que pasaron, a es la razon de depreciación de la camioneta y b es el precio inicial de la camioneta, b = $42,000.

Sabemos que después de 5 años, el precio de la camioneta es 21,000, entonces podemos resolver:

$21,000 = a*5 + $42,000

a*5 = $21,000 - $42,000 = -$21,000

a = -$21,000/5 = -$4,200

Esto significa que el precio decae $4,200 por año

4 0
2 years ago
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