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1 year ago

6

Christopher bought a new watch at the store when they were having a 30% off sale.If the regular price of the watch was $48, how

much did Christopher pay with the discount (not including sales tax)?

1 answer:

solong [7]1 year ago

5 0

Answer:

$30 \div 100 \times 48 = 14.4 \\ 48 - 14.4 = 33.6$

therefore Christopher paid $ 33.6

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Evgesh-ka [11]

Answer:

Hello! I am also having trouble in algebra! From what I can see so far this is what the problem should look like...

Step-by-step explanation:

A. Yes, it s a linear function because it matches the equation y=mx+b

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2 years ago

Ozzie is starting his own part time business. He plans to earn $20 per hour. He has the following expenses each month, $500 for

CaHeK987 [17]

To get $555 he would have to work 27.75 hours or round it up to 28 hours but to get enough money for ALL his expenses he would need to work 32.25 hours or round it up to 33

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2 years ago

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Three small circles C1, C2, and C3, each with radius 0.1 and centered at the origin are in the xy-, yz-, and xz-planes, respecti

den301095 [7]

Curl is defined as:

$\bigtriangledown \times F=\frac{ \int F.dr}{Area}$

Which can be rewritten as:

$\frac{ \int F.dr}{Area}=\frac{ \int_{C_1} Fdr}{Area}\widehat{k}+\frac{ \int_{C_2} Fdr}{Area}\widehat{i}+\frac{ \int_{C_3} Fdr}{Area}\widehat{j}$

This is because C1 lies on the xy plane and thus it's unit vector will be $\widehat{k}$ .

By similar arguments the rest will follow too.

Now, area of each circle will be: $\pi \times (0.1)^2=0.01 \pi$

Therefore, Curl, as per our definition will be:

$\frac{\int F.dr}{Area}=\frac{0.01\pi}{0.01\pi}\widehat{k}+\frac{0.4\pi}{0.01\pi}\widehat{i}+\frac{5 \pi}{0.01\pi}\widehat{j}$

Thus, Curl= $40\pi \widehat{i}+500\pi \widehat{j} +\widehat{k}$

Which is the required answer.

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2 years ago

The population of Rock Springs is growing at a constant rate. The expression represents the increase in population in x years. 4

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The expression is given such as:
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2 years ago

A web-based company has a goal of processing 90 percent of its orders on the same day they are received. If 434 out of the next

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Answer:

We conclude that a web-based company are not exceeding their goal of 90%.

Step-by-step explanation:

We are given that a web-based company has a goal of processing 90 percent of its orders on the same day they are received.

434 out of the next 471 orders are processed on the same day.

Let p = <u><em>proportion of orders processing on the same day they are received.</em></u>

SO, Null Hypothesis, $H_0$ : p $\leq$ 0.90 {means that they are not exceeding their goal of 90%}

Alternate Hypothesis, $H_0$ : p > 0.90 {means that they are exceeding their goal of 90%}

The test statistics that would be used here <u>One-sample z test for</u> <u>proportions</u>;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of orders that are processed on the same day = $\frac{434}{471}$ = 0.92

n = sample of orders = 471

So, <u><em>the test statistics</em></u> = $\frac{0.92-0.90}{\sqrt{\frac{0.92(1-0.92)}{471} } }$

= 1.599

The value of z test statistics is 1.599.

<u>Now, at 0.025 significance level the z table gives critical value of 1.96 for right-tailed test.</u>

Since our test statistic is less than the critical value of z as 1.599 < 1.96, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that a web-based company are not exceeding their goal of 90%.

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1 year ago