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1 year ago

Let p: x=4 let q:y=-2

Mathematics

1 answer:

ICE Princess25 [194]1 year ago

6 0

Question:

Let p: x = 4 Let q: y = −2 Which represents "If x = 4, then y = −2”? p ∨ q p ∧ q p → q p ↔ q

Answer:

Option c: p → q

Explanation:

Option a: p ∨ q

p ∨ q means that either p is true or q is true or both are true.

Hence, Option a is not the correct answer.

Option b: p ∧ q

p ∧ q means that both p and q are true.

Hence, Option b is not the correct answer.

Option c: p → q

p → q means that if p is true, then q is also true.

Hence, Option c is the correct answer.

Option d: p ↔ q

p ↔ q means that if p is true, then q is true. If q is true, then p is true.

Hence, Option d is not the correct answer.

Thus, p → q is the correct option.

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The first term of a finite geometric series is 6 and the last term is 4374. The sum of all the term os 6558. find the common rat

Oliga [24]

A geometric series is written as $ar^n$ , where $a$ is the first term of the series and $r$ is the common ratio.

In other words, to compute the next term in the series you have to multiply the previous one by $r$ .

Since we know that the first time is 6 (but we don't know the common ratio), the first terms are

$6, 6r, 6r^2, 6r^3, 6r^4, 6r^5, \ldots$ .

Let's use the other information, since the last term is $4374 > 6$ , we know that $r>1$ , otherwise the terms would be bigger and bigger.

The information about the sum tells us that

$\displaystyle \sum_{i=0}^n 6r^i = 6\sum_{i=0}^n r^i = 6558$

We have a formula to compute the sum of the powers of a certain variable, namely

$\displaystyle \sum_{i=0}^n r^i = \cfrac{r^{n+1}-1}{r-1}$

So, the equation becomes

$6\cfrac{r^{n+1}-1}{r-1} = 6558$

The only integer solution to this expression is $n=6, r=3$ .

If you want to check the result, we have

$6+6*3+6*3^2+6*3^3+6*3^4+6*3^5+6*3^6 = 6558$

and the last term is

$6*3^6 = 4374$

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1 year ago

Your lab develops a synthetic compound that is extremely light but very durable. You test it by making a solid ball with a radiu

Maksim231197 [3]

The volume of a spherical shaped object is given by

$V= \frac{4}{3} \pi r^3$

Given that the <span>solid ball has a radius of 20.0 millimeters, the volume of the solid ball is given by

$V= \frac{4}{3} \pi(20)^3\approx33,510mm^3$

Therefore, the </span><span>closest to the volume of the synthetic compound ball, in cubic millimeters is 33,500 cubic milimeters.</span>

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2 years ago

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

bearhunter [10]

The question is incomplete. Here is the complete question:

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.

Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?

Answer:

40.13%

Step-by-step explanation:

Let 'A' be the event of not missing a target in 10 attempts.

Therefore, the complement of event 'A' is $\overline A=\textrm{Missing a target at least once}$

Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.

Now, $P(A)=0.95^{10}=0.5987$

We know that the sum of probability of an event and its complement is 1.

So, $P(A)+P(\overline A)=1\\\\P(\overline A)=1-P(A)\\\\P(\overline A)=1-0.5987\\\\P(\overline A)=0.4013=40.13\%$

Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.

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