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geniusboy [140]

1 year ago

14

Trisha and Malia went to the mall with their mom. Trisha spent $15.60 on a pair of sunglasses. Malia spent $29.80 more than Tris

ha on a new handbag. Their mom spent 2.5 times as much as Malia on an espresso machine for their kitchen. How much money did their mom spend on the espresso machine?

1 answer:

mr Goodwill [35]1 year ago

7 0

Answer:

$113.50

Step-by-step explanation

add $15.60 + $29.80 = $45.40
multiply $45.40 x 2.5 = $113.50

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Megan and Suzanne each have a plant. They track the growth of their plants for four weeks. Whose plant grew at a faster rate, an

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In science, rate is a<span> quantity measured with respect to another measured quantity. For the data given, we get the rate of each by calculating the slope. We do as follows:

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A hot air balloon is floating above a straight road. To estimate their height above the ground, the balloonists simultaneously m

san4es73 [151]

Answer:

$h=1.99 miles$

Step-by-step explanation:

Let's call $h$ the balloon's height above the ground and $b$ the horizontal distance between the balloon and the first milepost.

If the angle of the depression of this milepost is 24 degrees, we can say the following:

$tan(24)=\frac{h}{b}$

<em> $b=\frac{h}{tan(24)}$ (equation 1)</em>

For the next milepost, the horizontal distance between the balloon and tihs milepost will be $(b+1)miles$ and the angle of depression will be 20 degrees, so we can say the following

$tan(20)=\frac{h}{b+1}$

$b+1=\frac{h}{tan(20)}$

$b=\frac{h}{tan20}-1$

then, replacing from <em>equation 1</em>

$\frac{h}{tan(24)} =\frac{h}{tan(20)}-1$

$1 =\frac{h}{tan(20)}-\frac{h}{tan(24)}$

$1 =h*(\frac{1}{tan(20)}-\frac{1}{tan(24)})$

$h=\frac{1}{(\frac{1}{tan(20)}-\frac{1}{tan(24)})}$

Resolving, we'll find the value of $h$

$h=1.99 miles$

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A study of 25 graduates of four-year public colleges revealed the mean amount owed by a student in student loans was $55,051. Th

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Answer:

a

The 90% confidence interval is $52561.13 < \mu < 57540.8$

b

Confidence interval for the population men between <u>$52561.13</u> up to <u>$57540.8</u>

Step-by-step explanation:

From the question we are told that

The sample size is $n = 25$

The sample mean is $\= x = \$ 55,051$

The standard deviation is $\sigma = \$ 7,568$

Given that the confidence level is 90% then the level of confidence is mathematically represented as

$\alpha = 100 -90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table the values is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{ 7568}{ \sqrt{ 25} }$

$E = 2489.9$

The 90% confidence interval is mathematically evaluated as

$\= x -E < \mu < \= x +E$

substituting values

$55051 - 2489.8 < \mu < 55051 + 2489.8$

$52561.13 < \mu < 57540.8$

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Step-by-step explanation:

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