To solve for x, you must first understand how the median was calculated out of the given set of numbers. Without looking at the given median value, we can see that we cannot get the median by process of elimination since there are an even amount of numbers in this particular set. Therefore, we must average the two closest values to what should be the median.
In this case, the values are "45" and "x". If we pretend that we know the value of the variable "x" (for example we will pretend that x is 55), then we should have an equation that looks like this: (45+55) ÷ 2 = [median]. What this equation is doing is adding the two closest values to the median (45 and 55) and dividing it by 2, the number of values we are averaging. Now we can solve this equation and simplify it to 100 ÷ 2 which is 50, our median.
So if they give us the median instead of the x value, then we can rewrite the equation to fit your request: (45+x) ÷ 2 = 51. Now we can solve for x:
1. Multiply by 2
(45+x) = 102
2. Subtract 45
x = 57
The x value for your question is 57.
Answer:
72
Step-by-step explanation:
We are assuming that all girls in the group bought the same number of items.
Therefore, we need to find the highest common factor of 72, 144 and 216.
HCF
72 = 2 * 2 * 2 * 3 * 3
144 = 2 * 2 * 2 * 2 * 3 * 3
216 = 2 * 2 * 2 * 3 * 3 * 3
The product of the emboldened numbers is the highest common factor.
That is:
2 * 2 * 2 * 3 * 3 = 72
Therefore, the largest possible number of girls in the group is 72.
Answer:
8 helicopters at most
Step-by-step explanation:
I worked on this problem and that was the answer not 99 like the other.
I hope this helps you
Area =base.height
246=base.20,5
base=12
I guess itz B because with the rest, a number can be added to get exactly 50. Example C. y= 50x. x could be 1 which is still 50 and D. y=50-x and x could be 0 which is still 50 whiles A. y=50 remains 50
