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Liula [17]
2 years ago
5

The heat in the house is set to keep the minimum and maximum temperatures (in degrees Fahrenheit) according to the equation |x –

72.5| = 4. What are the minimum and maximum temperatures in the house?
Mathematics
2 answers:
solniwko [45]2 years ago
8 0

Answer:

Minimum temperature is 68.5 ° and maximum temperature is 76.5 °

Step-by-step explanation:

Given :

|x – 72.5| = 4.

When the Temperature of x is minimum So the Minimum temperature  is

|x - 72.5| = 4\\it\  can \ be \ written \ as \\72.5-x=4\\-x=4-72.5\\x=68.5

When the Temperature of x is maximum So the Maximum Temperature is

|x -72.5| = 4\\x-72.5=\ 4\\x=72.5+4\\x=76.5

Therefore The minimum temperature is 68.5 ° and the maximum temperature is 76.5 °

Tems11 [23]2 years ago
3 0

Answer:

b

Step-by-step explanation:

becasue I did and and check with teacher

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6051 was rounded to the nearest one. What is the lower bound?
shusha [124]

Answer:

6050

Step-by-step explanation:

3 0
2 years ago
Each day, X arrives at point A between 8:00 and 9:00 a.m., his times of arrival being uniformly distributed. Y arrives independe
astraxan [27]

Answer:

Y will arrive earlier than X one fourth of times.

Step-by-step explanation:

To solve this, we might notice that given that both events are independent of each other, the joint probability density function is the product of X and Y's probability density functions. For an uniformly distributed density function, we have that:

f_X(x) = \frac{1}{L}

Where L stands for the length of the interval over which the variable is distributed.

Now, as  X is distributed over a 1 hour interval, and Y is distributed over a 0.5 hour interval, we have:

f_X(x) = 1\\\\f_Y(y)=2.

Now, the probability of an event is equal to the integral of the density probability function:

\iint_A f_{X,Y} (x,y) dx\, dy

Where A is the in which the event happens, in this case, the region in which Y<X (Y arrives before X)

It's useful to draw a diagram here, I have attached one in which you can see the integration region.

You can see there a box, that represents all possible outcomes for Y and X. There's a diagonal coming from the box's upper right corner, that diagonal represents the cases in which both X and Y arrive at the same time, under that line we have that Y arrives before X, that is our integration region.

Let's set up the integration:

\iint_A f_{X,Y} (x,y) dx\, dy\\\\\iint_A f_{X} (x) \, f_{Y} (y) dx\, dy\\\\2 \iint_A  dx\, dy

We have used here both the independence of the events and the uniformity of distributions, we take the 2 out because it's just a constant and now we just need to integrate. But the function we are integrating is just a 1! So we can take the integral as just the area of the integration region. From the diagram we can see that the region is a triangle of height 0.5 and base 0.5. thus the integral becomes:

2 \iint_A  dx\, dy= 2 \times \frac{0.5 \times 0.5 }{2} \\\\2 \iint_A  dx\, dy= \frac{1}{4}

That means that one in four times Y will arrive earlier than X. This result can also be seen clearly on the diagram, where we can see that the triangle is a fourth of the rectangle.

6 0
2 years ago
A circle with radius of \greenD{6\,\text{cm}}6cmstart color #1fab54, 6, start text, c, m, end text, end color #1fab54 sits insid
Diano4ka-milaya [45]

Answer: 141 cm^{2}

Step-by-step explanation:

We have two circles:

Cirlce 1, with a radius r=6 cm and area A_{1}:

A_{1}=\pi r^{2}

And Cicle 2, with a radius R=9 cm and area A_{2}:

A_{1}=\pi R^{2}

Since Circle 1 is inside Circle 2 and assuming the area of the shaded region is the shown in the attached image, its area is:

A=A_{2}-A_{1}=\pi R^{2}-\pi r^{2}

A=\pi (R^{2}- r^{2})

A=\pi ((9cm)^{2}- (6cm)^{2})

Finally:

A=141.37 cm^{2} \approx 141 cm^{2}

3 0
2 years ago
Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its
Savatey [412]
The graph would almost look like this

8 0
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Museum admission fee = $12.50

Lunch = 5.95 + 1.25 + 1.69 = $8.89
Tax = 7.25% of 8.89 = 0.66675
Tip = 15% of 8.89 = 1.3335
Total spend for lunch = 8.89 + 0.66675 + 1.3335 = 10.89

Total spend for the day = 10.89 + 12.50 = $23.39
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2 years ago
Read 2 more answers
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