Answer:
Let t be the number of ten dollar bills.
o×6+5=t
If you need it without t, then it's:
o×6+5
Step-by-step explanation:
Let t be the number of ten dollar bills.
o×6+5=t
We get this because the question said that there were more ten-dollar bills than 6 times the number of one-dollar bills.
Answer:
E: The study was not comparative—only one treatment was used.
Step-by-step explanation:
Well-designed experiments should involve comparisons of at least two treatment groups, one of which could be a control group.
9514 1404 393
Answer:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
142 fish
Step-by-step explanation:
A) The differential equation is modified by adding a -50 fish per year constant term:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
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B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.
(0.4/1200)(N)(1200-N) -50 = 0
N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient
N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square
(N -600)^2 = 210,000 . . . . . simplify
N = 600 + √210,000 ≈ 1058
This steady-state number of fish is ...
1200 - 1058 = 142 . . . . below the original carrying capacity
Multiply $30 by .25 you get, it's $7.50so you subtract $7.50 from $30 and you get $22.50. Then multiply 2 (sweaters) by $22.50 and you get $45,but wait you still have to multiply that sales tax so you multiply .04 by $45 and you get $1.80, later you subtract $1.80 from $45 and you get $43.20(the cost of the two sweaters)
I did part1 only cuz' no I have no time left Sorry for the inconvenience
