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2 years ago

. Steve drove for 812 hours at 72 miles per hour. How much distance did he travel?

Mathematics

2 answers:

DedPeter [7]2 years ago

5 0

Answer:

If Steve drives for 812 hours at 72 miles per hour, he drives 58,464 miles in total.(Side Note: if you mean 8 1/2 hours then it's 612 miles

Step-by-step explanation:

To find distance dealing with time and speed, we can use the formula d=rt.

D= Distance

R= Speed

T= Time

Now we plug in our values! D=72 × 812 and we get D= 58,464 miles or if you meant 8 1/2 hours, then it's 612 miles

Hope this helps! :)

Mazyrski [523]2 years ago

4 0

Answer:

58464

Step-by-step explanation:

Multiply the two numbers

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Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.

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we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

In this problem

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then

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$(x-2)\\ (x-3)\\ (x-5)$

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$x=2\\ x=3\\ x=5$

each occurring once.

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Answer:

$P(5.5$

And we can find this probability using the normal standard distribution or excel and we got:

$P(-2.769$

Step-by-step explanation:

For this case we assume the following complete question: "The pucks used by the National Hockey League for ice hockey must weigh between 5.5 and 6 ounces. Suppose the weights of pucks produced at a factory are normally distributed with a mean of 5.86 ounces and a standard deviation of 0.13ounces. What percentage of the pucks produced at this factory cannot be used by the National Hockey League? Round your answer to two decimal places. "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(5.86,0.13)$