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2 years ago

(PLEASE HELP URGENT!)

Mathematics

1 answer:

Olin [163]2 years ago

8 0

x f(X) g(x)
2.5 2 1.25
1.5 0 -2.75
2.75 2.5 2.56
2.8 2.6 2.84
2.77 2.54 2.67
2.73 2.46 2.45 <<<<<<< Answer.

I've included a graph to show you another way that you could get closer quicker.

The red line is y = 2x - 3
The blue line is y = x^2 - 5

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N JKL, mJ = 90, mK = 30, and mL = 60. Which of the following statements about JKL are true?

Leya [2.2K]

KL=2*JL
I tried to find the rest of the question online, and I'm not sure if radicals couldn't show up or something, but attached is an image of the rules for a 30-60-90 triangle, so hopefully this helps.

3 0

2 years ago

A salesman normally makes a sale (closes) on % of his presentations. Assuming the presentations are independent, find the pro

Tamiku [17]

Answer:

$(a)\ 0.0864$

$(b)\ 0.096$

$(c)\ 0.24$

$(d)\ 0.936$

Step-by-step explanation:

Given

$p \to$ close

$q \to$ fail to close

$p = 60\%$

$p = 0.60$

First, calculate the value of q

Using complement rule

$q = 1 - p$

$q = 1 - 0.60$

$q = 0.40$

So, we have:

$p = 0.60$ and $q = 0.40$

Solving (a): Fails to close on the 4th attempt

This means that he closes the first three attempts. The event is represented as: p p p q

So, we have:

$Pr = p*p*p*q$

$Pr = p^3*q$

$Pr = 0.60^3*0.40$

$Pr = 0.0864$

Solving (b): He closes for the first time on the 3rd attempt

This means that he fails to close the first two attempts. The event is represented as: q q p

So, we have:

$Pr = q * q * p$

$Pr = q^2 * p$

$Pr = 0.40^2 * 0.60$

$Pr = 0.096$

Solving (c): First he closes is his 2nd attempt

This means that he fails to close the first. The event is represented as: q p

So, we have:

$Pr = q * p$

$Pr = 0.40 * 0.60$

$Pr = 0.24$

Solving (d): The first he close is one of his 3 attempts

To do this, we make use of complement rule

The event that he does not close any of his first three attempts is: q q q

The probability is:

$Pr = q*q*q$

$Pr = q^3$

The opposite is that the first he closes is one of the first three

So, we have:

$Pr' = 1- Pr$ --- complement rule

$Pr' = 1- q^3$

$Pr' = 1- 0.40^3$

$Pr' = 1- 0.064$

$Pr' = 0.936$

4 0

2 years ago

7. During the Middle Ages, people often used grains, scruples, and drahms to measure the weights of different medicines. If 120

Serjik [45]

Answer:

5 drahms.

Step-by-step explanation:

From the question given above, the following data were obtained:

120 grains = 6 scruples

6 scruples = 2 drahms

300 grains (in drahms) =..?

From the above data,

120 grains = 6 scruples

6 scruples = 2 drahms

Therefore,

120 grains = 2 drahms

Thus, we can obtain 300 grains in drahms as follow:

120 grains = 2 drahms

Therefore,

300 grains = 300 grains × 2 drahms /120 grains

300 grains = (300 × 2)/120 drahms

300 grains = 5 drahms

Therefore, 300 grains is equivalent to 5 drahms.

5 0

2 years ago

Math 9:The floor of conference hall can be covered completely with tiles. Its length is 36 ft longer than its width. The area of

valentina_108 [34]

What is the question?
I'm assuming it is to find the length and width.
+_= plus or minus
(X+36)
____________
| |
(X) | |
|____________|

X^2+36X-2040<0
X<-36+_(36^2-4*-2040)^(1/2)
-----------------------------------
2
X<-18+_2((591)^(1/2))
This is probably not what you wanted, sorry

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2 years ago

A sidewalk bounds a circular playground at GeoCity Park. Parents can exercise by walking around on the sidewalk, while watching

Llana [10]

Answer:

125664.3 m²

I'm required 20 characters minimum

7 0

2 years ago

Read 2 more answers