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sukhopar [10]
2 years ago
7

kadeem and quinn both drive 25 miles. Kadeem drives at a constant speed of 50 miles an hour. Quinn drives at a constant speed of

75 miles an hour. Who takes longer to drive the 25 miles? How much loner?
Mathematics
1 answer:
Phantasy [73]2 years ago
8 0

Answer:

Kadeem will take 0.166 h more to complete the course.

Step-by-step explanation:

The speed is the rate at which the distance changes, when the speed goes up the distance changes more quickly, therefore if the distance is the same and the speed is higher the one who will take longer is the one that has less speed. In this case the one who will take longer to drive the 25 miles is Kadeem, since he's driving at 50 mph. In order to calculate how much longer we need to calculate the time at which each of them complete the course, this is shown below:

time = distance/speed

For Kadeem:

time = 25/50 = 0.5 h

For Quinn:

time = 25/75 = 0.334 h

The difference between the is 0.5 - 0.334 = 0.166 h.

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2 years ago
Compute the requested value. Choose the correct answer.
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2 years ago
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The owner of a manufacturing plant employs eighty people. As part of their personnel file, she asked each one to record to the n
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Answer:

<em>Mean of the sample = 27.83</em>

<em> The variance of the the sample = 106.96</em>

<em> </em><em>Standard deviation of the sample = 10.34</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given random sample of six employees

x     26    32    29    16     45    19

mean of the sample

x^{-} = \frac{26+32+29+16+45+19}{6} = 27.83

Mean of the given data = 27.83

<u>Step(ii):-</u>

<u>Given data</u>

x           :       26         32           29           16           45        19

x - x⁻     :      -1.83      4.17        1.17       -11.83     17.17    -8.83

(x - x⁻)²  :    3.3489   17.3889   1.3689   139.9489  294.80 77.9689

∑ (x-x⁻)²  =   534.8245

Given sample size 'n' =6

The variance of given data

           S²  = ∑(x-x⁻)² / n-1  

           S^{2}  = \frac{534.8245}{6-1} = 106.9649

The variance of the given sample = 106.9649

<u> Step(iii):-</u>

Standard deviation of the given data

S = \sqrt{variance} = \sqrt{106.9649} =10.3423

Standard deviation of the sample = 10.3423

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