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zhenek [66]
2 years ago
11

At 7 PM the temperature outside was -5°C what does |-5| represent in this situation Plz answer fast!!

Mathematics
2 answers:
ra1l [238]2 years ago
7 0

Answer:The temperature at 7 PM

Step-by-step explanation:

Vitek1552 [10]2 years ago
6 0

Answer: Temp at 7 PM




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On a coordinate plane, a circle has a center at (negative 2, 0). Point (negative 2, 4) lies on the circle. Distance formula: Sta
vivado [14]

Answer:

its B on Ed

Step-by-step explanation:

4 0
2 years ago
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You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh
lorasvet [3.4K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 2.35

x2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.82

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.075

Alpha = 5% = 0.05

Since alpha, 0.05 < than the p value, 0.075, then we would fail to reject the null hypothesis.

4 0
2 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
2 years ago
Javier uses 1/8 teaspoons of nutmeg for each loaf of banana bread he makes. How many loaves of banana bread can javier make with
Reil [10]
If you have 1/8 in every loaf and 1 teaspoon of nutmeg is 8/8 and you have 4 of those think how much is 8/8 x 4.
8 0
2 years ago
Read 2 more answers
. Donny had a 10-foot board. He used the board to make two shelves. One shelf measured 4 feet 7 inches wide and the other shelf
liberstina [14]

Answer:

The length of the missing piece is 2 ft 3 inches

Step-by-step explanation:

Here in this question, we are interested in calculating the length of the remaining piece of the board given that we have the total length of the board and two other pieces.

Mathematically, the remaining piece length can be calculated by subtracting the lengths of the known pieces

That would be;

10 ft - 4 ft 7 inches - 3 ft 2 inches

In a foot there are 12 inches

Thus

10 ft = 10 * 12 = 120 inches

4 ft 7 inches = 4(12) + 7 = 55 inches

3 ft 2 inches = 3(12) + 2 = 36 + 2 = 38 inches

Thus the length of the remaining piece would now be;

120 -55 -38 = 27 inches

That is same as 24 + 3 inches

24 inches = 2 ft

So 27 inches = 2 ft 3 inches

3 0
2 years ago
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