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1 year ago

Sean pays £10 for 24 chocolate bars. He sells all 24 chocolate bars for 50p each.

Mathematics

1 answer:

VladimirAG [237]1 year ago

4 0

Answer:

the percentage profit is 20%

Step-by-step explanation:

Given that

Sean paid £10 for 24 chocolate bars

He sold all 24 chocolate bars for 50p each

we need to find out the percentage profit

Since he paid £10 and sale value is (24 × 0.50) i.e. £12

So, the percentage profit is

= (£12 - £10) ÷ (£10)

= 20%

Hence, the percentage profit is 20%

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The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c

boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

$p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!}$ for x = 0, 1, 2, ...

where $\lambda$ , the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is $1.2 \cdot 3 =3.6$

The probability of exactly three flaws in 150 m of cable is

$P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246$

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is $1.2 \cdot 2 =2.4$

$P(X\geq 2)=1-P(X$

$P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155$

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

$P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143$

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

$(0.36143)(0.36143) = 0.13063$

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1 year ago

How many more barrels of gasoline then diesel were produced last year gasoline 34% diesel 29% total crude oil -60 million barrel

MArishka [77]

Answer: 3 million barrels

Step-by-step explanation:

Given :- Total crude oil= 60 million barrels

Quantity of gasoline = 34% of total crude oil

$=0.34\times60\text{ million barrels}\\=20.4\text{ million barrels}$

Quantity of diesel = 29% of total crude oil

$=0.29\times60\text{ million barrels}\\=17.4\text{ million barrels}$

Clearly, Quantity of gasoline is more than Quantity of diesel

difference = Quantity of gasoline-Quantity of diesel

$20.4\text{ million barrels}-17.4\text{ million barrels}\\=3\text{ million barrels}$

Therefore, The production of gasoline is 3 million barrels more than diesel last year.

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1 year ago

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A ship anchored in a port has a ladder which hangs over the side. The length of the ladder is 200cm, the distance between each r

bulgar [2K]

Answer:

The answer to your question is 8 h

Step-by-step explanation:

Data

length of the ladder = 200 cm

distance between each rung = 20 cm

rate = 10 cm/h

fifth rung = ?

Process

1.- Calculate the total distance the tide must rise

distance = 20 cm x 4

= 80 cm because the first rung touches the water

2.- Calculate the time

rate = distance / time

-Solve for time

time = distance / rate

-Substitution

time = 80 cm / 10cm/h

-result

time = 8 h

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1 year ago

If h(x) = 6 – x, what is the value of (h circle h) (10)?

Marta_Voda [28]

Answer:

Step-by-step explanation:

hoh(x) = h(h(x)) = 6 - h(x) = 6 - (6-x) = 6 - 6 + x = x

then

hoh(x) = x

then

hoh(10) = 10

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1 year ago

Carlos biked StartFraction 139 over 8 EndFraction miles on Saturday and StartFraction 135 over 7 EndFraction miles on Sunday. On

melomori [17]

Answer:

Carlos rode further than on Saturday by 107/56 miles.

Step-by-step explanation:

i did the quiz lol

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