I am not sure about this but here goes nothing: d=2.5t+2.2 is very familiar to y=mx+b y=d m=2.5 x=t b=2.2 to find a new quasion we substitute d and t into place wich equals 1=2.5(0)+b simplification and you get b=1 so your answer is d=2.5t+1
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
Answer:
No options
Step-by-step explanation:
Knowing that V=in/min = x(t)/t and according to the graph,
V=20in/20min=in/min, so
No options since speed is not inches per minute, spedd (V) = inches over minutes
Part A)
Total stores = 362 + 66 = 428
362 / 428 = 0.845 = 84.5% = 85%
66 / 428 = 0.154 = 15.4% = 15%
Yes this is consistent with the percentages shown in the first table.
Part B)
Total stores : 197 +115 = 312
197 / 312 = 0.631 = 63.1% = 63%
115 / 312 = 0.368 = 36.8% = 37%
The percentage for current stores is less than what is shown in the first table, so this would not be consistent.
Part C )
Percentage of new stores for the Northeast = 60 / 310 = 19%
The percentage of new stores for The Midwest and Northeast are below 25%, but the percentage of new stores in the South is above 25%, so the additional training wouldn't be required for the South, but should be required for the other two areas.