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neonofarm [45]
1 year ago
8

There are 20 alligators in the swamp. Each year, the number of alligators increases by 25%. There are 25 crocodiles in the swamp

. Each year, 10 new crocodiles join the swamp.
Part A: Write functions to represent the number of alligators and crocodiles in the swamp throughout the years. (4 points)

Part B: How many alligators are in the swamp after 4 years? How many crocodiles are in the swamp after the same number of years? (2 points)

Part C: After approximately how many years is the number of alligators and crocodiles the same? Justify your answer mathematically. (4 points)
Mathematics
1 answer:
myrzilka [38]1 year ago
7 0
Part A: f(x)=(5)x+20(alligators) and f(x)=(10)x+25(crocodiles)

Part B: f(x)=(5)(4)+20(alligators) and f(x)=(10)(4)+25(crocodiles)
Alligators: 40 and Crocodiles: 65

Part C: None because the rate of the alligators won't catch up with the rate of crocodiles.
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2 years ago
Ice cream usually comes in 1.5-quart boxes (48 fluid ounces), and ice cream scoops hold about 2 ounces. However, there is some v
Troyanec [42]

Answer:

(a) The expected value and standard deviation of the amount of ice cream served at the party are 54 ounces and 1.25 ounces respectively.

(b) The expected value and standard deviation of the amount of ice cream left in the box after scooping out one scoop are 46 ounces and 1.031 ounces respectively.

(c) Because the variance of each variable is dependent on the other.

Step-by-step explanation:

The random variable <em>X</em> and <em>Y</em> are defined as follows:

<em>X</em> = amount of ice cream in the box

<em>Y</em> = amount of ice cream scooped out

The information provided is:

E (X) = 48

SD (X) = 1

V (X) = 1

E (Y) = 2

SD (Y) = 0.25

V (Y) = 0.0625

(a)

The total amount of ice-cream served at the party can be expressed as:

<em>X</em> + 3<em>Y</em>.

Compute the expected value of (<em>X</em> + 3<em>Y</em>) as follows:

E(X+3Y)=E(X)+3E(Y)\\= 48+(3\times2)\\=48+6\\=54

Compute the variance of (<em>X</em> + 3<em>Y</em>) as follows:

V(X+3Y) = V (X)+3^{2}V(Y)+2\times 3Cov (X,Y)\\=1+(9\times0.0625)+0\\=1.5625

Then the standard deviation of (<em>X</em> + 3<em>Y</em>) is:

SD(X + 3Y) =\sqrt{V(X + 3Y)}\\\sqrt{1.5625}\\=1.25

Thus, the expected value and standard deviation of the amount of ice cream served at the party are 54 ounces and 1.25 ounces respectively.

(b)

The amount of ice-cream left in the box after scooping out one scoop is represented as follows:

<em>X</em> - <em>Y</em>.

Compute the expected value of (<em>X</em> - <em>Y</em>) as follows:

E(X-Y)=E(X)-E(Y)\\=48-2\\=46

Compute the variance of (<em>X</em> - <em>Y</em>) as follows:

V(X - Y) =V(X)+V(Y)-2Cov(X,Y)\\=1+0.0625-0\\=1.0625

Then the standard deviation of (<em>X</em> - <em>Y</em>) is:

SD(X-Y) =\sqrt{V(X -Y)}\\\sqrt{1.0625}\\=1.031

Thus, the expected value and standard deviation of the amount of ice cream left in the box after scooping out one scoop are 46 ounces and 1.031 ounces respectively.

(c)

The variance of the sum or difference of two variables is computed by adding the individual variances. This is because the variance of each variable is dependent on the others.

7 0
2 years ago
Juan buys 2.8 pounds of turkey. The turkey costs $4.55 for each pound. How much does Juan spend for the turkey?
nadya68 [22]

Answer:12.75

Step-by-step explanation:

2.8X4.55

4 0
2 years ago
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The answer is 7 I’m pretty sure
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1 year ago
Diana sold 336 muffins at the bake sale.Bob sold 287 muffins.Bob estimates that he sold 50 fewer muffins than Diana.how did he e
malfutka [58]

Step-by-step explanation:

Since we have given that

Number of muffins Diana sold at the bake sale = 336

Number of muffins Bob sold at the bake sale = 287

Now, here we are using the method of estimation i.e. rounding the integers to nearest ones.

By estimation, we get

Number of muffins Diana sold at the bake sale = 340

Number of muffins Bob sold at the bake sale = 290

So,

Difference between them is given by

340-290\\=50

Hence, Bob sold 50 fewer muffins than Diana.

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1 year ago
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