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mash [69]
2 years ago
10

Which will result in a difference of squares? (negative 7 x + 4)(negative 7 x + 4) (negative 7 x + 4)(4 minus 7 x) (negative 7 x

+ 4)(negative 7 x minus 4) (negative 7 x + 4)(7 x minus 4)
Mathematics
2 answers:
yKpoI14uk [10]2 years ago
4 0

Answer:

Option C

Step-by-step explanation:

nevsk [136]2 years ago
3 0

Answer:

(negative 7 x + 4)(negative 7 x minus 4)

Step-by-step explanation:

Consider two real numbers a and b. A difference of squares involving a and b is usually given as;

a^{2}-b^{2}

The difference of the two squares above can be factored to yield;

(a-b)(a+b)

This implies that in order to have the difference of squares we must have a product involving the difference and the sum of the numbers.

The expression;

(negative 7 x + 4)(negative 7 x minus 4) can also be written as ( 4 - 7x) ( -4 - 7x)

( 4 - 7x) ( -4 - 7x) = ( 4 - 7x) (-1( 4 + 7x)) = -1 *( 4 - 7x) ( 4 + 7x)

Expanding the last expression yields;

-1 (16 + 28x -28x - 49x^2) = -1 (16 - 49x^2) = 49x^2 - 16 which is in deed a difference of squares

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Riley and Jace work at a dry cleaners ironing shirts. Riley can iron 25 shirts per hour, and Jace can iron 30 shirts per hour. R
oee [108]

Answer:

  • 25r +30j = 460
  • r - j = 3

Step-by-step explanation:

Let r and j represent Riley's hours and Jace's hours, respectively. The equations could be ...

  25r +30j = 460

  r - j = 3

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The solution is (r, j) = (10, 7).

5 0
2 years ago
What property describes the number sentence 6+0 = 6
zmey [24]
That is the Identity Property of Addition.
If it is adding and the whole number stays the same it is Identity Property of Addition.
If it is multiplying then it would be the Identity Property of Multipulcation. For example for this problem it would be 6x1 in multipulcation in which the whole number would stay the same.
Here are descriptions of all the properties:
https://wikis.engrade.com/mathproperties1

7 0
2 years ago
Read 2 more answers
The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking
Anna [14]

Answer:

The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 160, \pi = \frac{14}{160} = 0.088

88% confidence level

So \alpha = 0.12, z is the value of Z that has a pvalue of 1 - \frac{0.12}{2} = 0.94, so Z = 1.555.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.088 - 1.555\sqrt{\frac{0.088*0.912}{160}} = 0.053

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.088 + 1.555\sqrt{\frac{0.088*0.912}{160}} = 0.123

The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)

6 0
2 years ago
AC CE and D is the midpoint of CE. IF CE 10x + 18, DE =7x -1, and BC = 9x - 2, find AB, AB =
Anastasy [175]

Answer:

<h3>      If you mean: AC=CE, the answer is:  AB = 24</h3>

Step-by-step explanation:

D is the midpoint of CE, then

CD = DE = 0.5CE = 0.5(10x+18) = 5x + 9

So:   5x + 9 = 7x - 1

            -9          -9

        5x  =  7x - 8

        -7x      -7x

       -2x  =  -8

      ÷(-2)       ÷(-2)        

          x  =  4

AC = CE = 10x + 18 = 40 + 18 = 58

BC = 9x - 2 = 36 - 2= 34

AB = AC - BC = 58 - 34 = 24

4 0
2 years ago
Jack is 27 years older than Susan. In 5 years he will be 4 times as old as she is. Find the present ages of jack and Susan
riadik2000 [5.3K]
X - Jack's age
y - Susan's age

Jack is 27 years older than Susan.
x=y+27

In 5 years he will be 4 times as old as she is.
x+5=4(y+5)

The system of equations:
x=y+27 \\ x+5=4(y+5) \\ \\ \hbox{substitute y+27 for x in the 2nd equation:} \\ y+27+5=4(y+5) \\ y+32=4y+20 \\ y-4y=20-32 \\ -3y=-12 \\ y=\frac{-12}{-3} \\ y=4 \\ \\ x=y+27=4+27=31

Jack is 31 years old and Susan is 4 years old.
5 0
2 years ago
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