Raquel throws darts at a coordinate grid centered at the origin. Her goal is to create a line of darts. Her darts actually hit t
he coordinate grid at (–5, 0), (1, –3), (4, 5), (–8, –6), (0, 2), and (9, 6). Which equation best approximates the line of best fit of the darts? y = 0.6x + 0.6 y = 0.1x + 0.8 y = 0.8x + 0.1 y = 0.5x + 0.6
2 answers:
Solution:
The points at which Raquel Darts hit the coordinate grid having center at the origin are (–5, 0), (1, –3), (4, 5), (–8, –6), (0, 2), and (9, 6).
As we can see that not all points are collinear.
As line of best fit is the the line which passes through some points , may be not through the single point, or all the points.
Plotting all the options on coordinate grid i.e on a scatter plot and then determining , the line of best fit of the darts is
y= 0.6 x + 0.6 →→Option (A), the reason being it passes through a point (9,6).
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Answer:
a)
b)
c)
d)
e)
f)
Step-by-step explanation:
- M(x) = 1 if the person x came to the meeting, and 0 otherwise.
- O(x) = 1 if the person is an officer of the club and 0 otherwise.
- D(x) = 1 if the person has paid hid/her club dues and 0 otherwise.
Lets also call C the set given by the members of the club. C is the domain of the functions M, O and D.
a) If someone is not an officer, the there should be at least one value x such that O(x) = 0. This can be expressed by logic expressions this way
b) If all the officers came on time to the meeting, then for a value x such that O(x) = 1, we also have that M(x) = 1. Thus, the set of officers of the Club is contained on the set of persons which came to the meeting on time, this can be written mathematically this way:
c) If everyone was in time for the meeting, then C is equal to the set of persons who came to the meeting on time, or, equivalently, the values x such that M(x) = 1. We can write that this way:
d) If everyone paid their dues or came on time to the meeting, then if we take the set of persons who came to the meeting on time and the set of the persons who paid their dues, then the union of the two sets should be the entire domain C, because otherwise there should be a person that didnt pay nor was it on time. This can be expressed logically this way:
e) If at least one person paid their dues on time and came on time to the meeting, then there should be a value x on C such that M(x) and D(x) are both equal to 1. Therefore
f) If there is an officer who did not come on time for the meeting, then there should be a value x in C such that O(x) = 1 (x is an officer), and M(x) = 0. As a result, we have
I hope that works for you!
Let's find the derivative of that hyperbola in order to find a slope formula to help us with this equation. We already have an x and y value. The derivative is found this way: 
so 
. The derivative supplies us with the slope formula we need to write the equation. Sub in the x value of 3 to find what the slope is: 
. So in our slope-intercept equation, x = 3, y = 1, and m = -1/3. Use these values to solve for b. 
so b = 2. The equation, then, for the line tangent to that hyperbola at that given point is 
Answer:
r = 3
Step-by-step explanation:
34r + 3r =111
add;
34r + 3r = 37r
37r = 111
dividedboth sides by;
answer;
r = 3