There are 3 choices for the bottom scoop. Then there are only 3 choices for the scoop above that (since one flavor has already been used), then 2 choices for the next scoop, and 1 choice for the final scoop. This gives a total of 18 <span>possible cones.
Hope this helps.
</span>
For this case we have the following expression:
The first step is to solve the quadratic term.
We have then:
Then, the second step is to subtract both resulting numbers:
We observe that the result obtained is a negative number.
Answer:
The result of the expression is given by:
The slope intercept form for this line would be in the form of y=mx+b. The slope is m and the y-intercept is b.
y = (slope)x + (y-intercept)
y = 2x - 3
So, the answer is C.
Hope I could help! Have a good one!
Answer:
The slope becomes 0.5625 and y intercept becomes 12.5.
$65.9375
Step-by-step explanation:
Given that
the total reimbursement function in terms of 
miles:
After the policy change, 5 more dollars are added and then total amount is multiplied by 1.25.
To find:
How to transform the graph of f.
Total reimbursement for a trip of 95 miles?
Solution:
can also be written as:
It is nothing but slope intercept form, comparing with 
M is the slope and C is the y intercept.
Slope of the graph is 0.45.
Y intercept is 5.
After change in the function, first of all add $5.
Now, multiply with 1.25
Resulting function becomes:
Kindly refer to the attached image for the graph of the two functions.
Now, the slope becomes 0.5625 and y intercept becomes 12.5. This is the transformation.
To find the reimbursement for a trip of 95 miles:
Put m = 95
An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or …show more content…
An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or half-moon status because at least 50 percent of its surface was illuminated. In the following nights, the Moon displayed characteristics of waxing gibbous as the light continued to grow across the moon’s surface from right to left. The Moon was nearing closer to the full moon phase on November 14th as only a very small dark shadow was visible on the left side.
The Moon takes 27.3 days (sidereal month) to complete its actual orbit around the Earth. Like the Sun, the Moon rises in the east and sets in the west each day.
