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Aleonysh [2.5K]
1 year ago
5

Jayne evaluated an expression that has a value of StartFraction 1 Over 729 EndFraction. Which expression could Jayne have evalua

ted? Check all that apply.
(negative 9) cube
9 Superscript negative 3
3 Superscript negative 6
(StartFraction 1 Over 9 EndFraction) Superscript negative 6
(one-third) Superscript negative 6
(Negative 3) Superscript negative 6
Mathematics
2 answers:
san4es73 [151]1 year ago
8 0

Answer:

-10     OVER 2-90

Step-by-step explanation:

coldgirl [10]1 year ago
6 0

Answer:

12.3649.p

Step-by-step explanation:

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1 point) As reported in "Runner's World" magazine, the times of the finishers in the New York City 10 km run are normally distri
BigorU [14]

Answer:

(a) E (X) = 61 and SD (X) = 9

(b) E (Z) = 0 and SD (Z) = 1

Step-by-step explanation:

The time of the finishers in the New York City 10 km run are normally distributed with a mean,<em>μ</em> = 61 minutes and a standard deviation, <em>σ</em> = 9 minutes.

(a)

The random variable <em>X</em> is defined as the finishing time for the finishers.

Then the expected value of <em>X</em> is:

<em>E </em>(<em>X</em>) = 61 minutes

The variance of the random variable <em>X</em> is:

<em>V</em> (<em>X</em>) = (9 minutes)²

Then the standard deviation of the random variable <em>X</em> is:

<em>SD</em> (<em>X</em>) = 9 minutes

(b)

The random variable <em>Z</em> is the standardized form of the random variable <em>X</em>.

It is defined as:Z=\frac{X-\mu}{\sigma}

Compute the expected value of <em>Z</em> as follows:

E(Z)=E[\frac{X-\mu}{\sigma}]\\=\frac{E(X)-\mu}{\sigma}\\=\frac{61-61}{9}\\=0

The mean of <em>Z</em> is 0.

Compute the variance of <em>Z</em> as follows:

V(Z)=V[\frac{X-\mu}{\sigma}]\\=\frac{V(X)+V(\mu)}{\sigma^{2}}\\=\frac{V(X)}{\sigma^{2}}\\=\frac{9^{2}}{9^{2}}\\=1

The variance of <em>Z</em> is 1.

So the standard deviation is 1.

8 0
1 year ago
At the beginning of the school year, Jamie had $500 in her savings account. She wants to have at least $200 left in the account
mario62 [17]

Answer:

Jamie should have reversed the inequality when using the division property of inequality.

Step-by-step explanation:

Jamie wrote

500 − 30x ≥ 200

Subtract 500 from both sides

500-500-30x ≥ 200-500

-30x ≥ -300

Divide both sides by -30

x ≥ 10

Instead of reversing the inequality when using the division property of inequality

500 − 30x ≥ 200

Subtract 500 from both sides

500-500-30x ≥ 200-500

-30x ≥ -300

Divide both sides by -30

x <or= 10

8 0
2 years ago
Read 2 more answers
The manager of a grocery store selected a random sample of 100 customers to estimate the average checkout time. The 90% confiden
lina2011 [118]

Answer:

c

Step-by-step explanation:

3 0
1 year ago
If x = 3 is a zero of the polynomial function f(x) = 2x3 + x2 − 25x + 12, which of the following is another zero of f(x)? ASAP
olasank [31]
If x = 3 is a solution, (x - 3) is a factor of f(x).
2x³ + x² - 25x + 12 ÷ (x - 3) [by long division] = 2x² + 7x - 4
so f(x) = (x - 3)(2x² + 7x - 4)
f(x) = (x - 3)(2x - 1)(x + 4)
so 'zeros', or more correctly solutions, are: x = 3, x = 1/2 and x = -4.
[by setting each of the factors equal to 0 and solving for x].
7 0
1 year ago
Two terms of an arithmetic sequence are $a_{12}=70$a12​=70​ and A sub 30 is equal to 124$a_{30}=124$a30​=124​ . Write an explici
Yanka [14]

Answer:

<h2>Tn = 34+3n</h2>

Step-by-step explanation:

The formula for finding the nth term of an arithmetic sequence is expressed as shown;

Tn = a+(n-1)d

a is the first term of the sequence

n is the number of terms

d is the common difference

If T₁₂ = 70 and T₃₀ = 124

T₁₂  = a+(12-1)d = 70

T₁₂  = a+11d = 70... (1)

Similarly;

T₃₀ = a + (30-1)d = 124

T₃₀ = a +29d = 124...(2)

Solving equation 1 and 2 simultaneously to get a and d.

Subtracting 2 from 1 we have;

29d - 11d = 124-70

18d = 54

d = 54/18

d = 3

Substituting d = 3 into equation 1 to get a we have;

a + 11(3) = 70

a + 33 = 70

a = 70-33

a = 37

The explicit rule for the nth term of the sequence can be gotten by substituting the value of a and d into the formula Tn = a+(n-1)d

Tn = 37+(n-1)*3

Tn = 37+3n-3

Tn = 34+3n

5 0
2 years ago
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