All categories

2 years ago

The number of gallons of gas that were in the tank minus 9 leaves 3 gallons

Mathematics

2 answers:

erastovalidia [21]2 years ago

7 0

To solve the missing number of the original amount of gallons that were in the tank is simply by adding the two numbers we have:

9+3= 12 gallons

To make sure 12 was the original number, subtract 12 from 9. 

12-9= 3 gallons 

So your answer to your question is 12 gallons!

Hope this helped! °ω°

a_sh-v [17]2 years ago

4 0

Answer:

I expect u wanna find the number of gallons ni the tank initially. If so, your answer is 12 gallons.

Step-by-step explanation:

Let the number of gallons in the tank be x.

Then,

x - 9 =3

x -9 +9 = 3+9

x = 12

Hope i helped u :p

You might be interested in

Which equation represents a proportional relationship with a constant of proportionality of 14? y = x + 14 y = 14x 14y = x y = x

Ivanshal [37]

For $y$ and $x$ to be the variables.

Equation that represents a proportional relationship with a constant or proportionality of 14 is : $y = 14x$

Here, $y$ and $x$ are proportional to each other with a constant of proportionality of 14

6 0

2 years ago

Read 2 more answers

Simplify three to the negative ninth divided by three to the negative twelfth.

frutty [35]

When you divide, the exponents subtract. -9 - (-12) = 3
3^3 = 27.

8 0

2 years ago

Read 2 more answers

In a relay race, the probability of the Galaxy team winning is 22%. In another unrelated relay race, the probability of the Kome

Shalnov [3]

Answer: There is probability of approximately 12% that Komets losing their race and the Galaxy winning their game.

Explanation:

Since we have given that

Probability of the Galaxy team wins = 22%

Probability of the Komets team wins = 47%

So, Probability of the Komets losing their race is given by

$100-47=53\%$

We need to find the probability of the Komets losing their and the Galaxy winning their game .

Let Event K : Komets losing their game

Event G : Galaxy winning their game

Since these are two independent events,

So,

$P(K\cap G)=P(K).P(G)\\\\P(K\cap G)=0.22\times 0.53\\\\P(K\cap G)=0.1166=0.12=12\%$

So, there is probability of 12% that Komets losing their race and the Galaxy winning their game.

3 0

2 years ago

Read 2 more answers

1:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. Wha

3241004551 [841]

Answer:

Step-by-step explanation:

1 ) No of total slips after addition = 11

8 slip with 3 on it

3 slips with 9 on it

expectation value = probability of 3 x 3 + probability of 9 x 9

= (8 / 11) x 3 + (3 / 11) x 9

24 / 11 + 27 / 11 = 4.636

2 )

No of total slips after addition = 12

8 slip with 3 on it

4 slips with 9 on it

expectation value = probability of 3 x 3 + probability of 9 x 9

= (8 / 12) x 3 + (4 / 12) x 9

2 + 3 = 5

3 )

Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n slips with 9 on it

expectation value = probability of 3 x 3 + probability of 9 x 9

= (8 / 10+n ) x 3 + (2+n / 10+n ) x 9 = 6

24 + 18 + 9n / 10 + n = 6

42 + 9n = 60 + 6n

3 n = 18

n = 6

4 )

Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n slips with 9 on it

expectation value = probability of 3 x 3 + probability of 9 x 9

= (8 / 10+n ) x 3 + (2+n / 10+n ) x 9 = 8

24 + 18 + 9n / 10 + n = 8

42 + 9n = 80 + 8n

n =

n = 38

Minimum of 38 has to be added .

6 0

2 years ago

Sean’s age and Helen’s age are in the ratio of 3:5. Two years ago, Helen was twice as old as Sean was then. Find their present a

PolarNik [594]

Lets Sean's age be x
Helen's age by y
x/y=3/5
x=3/5y

Second equation
2(x-2)=y-2

on solving u get Helen as 10 and Sean as 6

3 0

2 years ago